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Igoryamba
3 years ago
11

(4rxt – 8r2x + x²) – (6rx² + 5rxt – 2x)

Mathematics
1 answer:
Nuetrik [128]3 years ago
6 0

Answer:

sum = (4 - 5)rxt  -  (8 + 6) {rx}^{2}  + (1 + 2)x \\  =  - rxt - 14 {rx}^{2}  + 3x \\  \\ difference = (4 + 5)rxt + (6 - 8) {rx}^{2}  + ( - 2 + 1)x \\  = 9rxt - 2 {rx}^{2}  - x

\small{ \underline{{ \blue{becker}}}}

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When a quadrilateral is inscribed in a circle, the opposite angles are supplementary

The description of the angles in the quadrilaterals are:

  • b. m∠M = 55°, m∠J = 48°, and m∠L = 132°
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<h3>How to describe the angles</h3>

The quadrilateral is given as: JKLM

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The opposite angles are supplementary

So, we have:

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Next, we test the options

<u>Option (a)</u>

J + L = 180

125 + 35 = 160

This is not true

<u>Option (b)</u>

J + L = 180

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This is true

<u>Option (c)</u>

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<u>Option (d)</u>

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<u>Option (f)</u>

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Hence, the description of the angles in the quadrilaterals are (b), (d), (e) and (f)

Read more about inscribed quadrilaterals at:

brainly.com/question/26690979

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