(4rxt – 8r2x + x²) – (6rx² + 5rxt – 2x)

Mathematics

1 answer:

Nuetrik [128]2 years ago

6 0

Answer:

$sum = (4 - 5)rxt - (8 + 6) {rx}^{2} + (1 + 2)x \\ = - rxt - 14 {rx}^{2} + 3x \\ \\ difference = (4 + 5)rxt + (6 - 8) {rx}^{2} + ( - 2 + 1)x \\ = 9rxt - 2 {rx}^{2} - x$

$\small{ \underline{{ \blue{becker}}}}$

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