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Igoryamba
3 years ago
11

(4rxt – 8r2x + x²) – (6rx² + 5rxt – 2x)

Mathematics
1 answer:
Nuetrik [128]3 years ago
6 0

Answer:

sum = (4 - 5)rxt  -  (8 + 6) {rx}^{2}  + (1 + 2)x \\  =  - rxt - 14 {rx}^{2}  + 3x \\  \\ difference = (4 + 5)rxt + (6 - 8) {rx}^{2}  + ( - 2 + 1)x \\  = 9rxt - 2 {rx}^{2}  - x

\small{ \underline{{ \blue{becker}}}}

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