Answer:
the slope of the line in the graph is: 3
the y-intercept is: -4
the equation of the line is: y=3x-4
Step-by-step explanation:
If we find a point on the graph and count it until it reaches other solid point we get that you have to go up three and to the right by one. This solid point I looked at was (0,-4) and counted up to (-1,1). To find the slope, we have to simply count and use "rise over run". The rise is 3 for every 1 we run, making the slope 3/1 which is 3.
the y-intercept is the point on the graph that touches the y-axis on the graph. The only point on the graph that touches the y-axis is -4, making the y-intercept -4.
The equation for a graph is y=mx+b. m would be the slope and b would be the y-intercept. We know that the slope is 3 (m) and that the y-intercept is -4 (b). Putting them together, we get that the equation of the graph is y=3x-4.
To answer this question you can create an equation in terms of the number of zucchini that were planted. Each other plant gives information that can relate to the number of zucchini plants.
# of cucumbers + # of tomatoes + # of zucchini
2z + 2z + 8 + z = 43
5z + 8 = 43
-8 -8
<u>5z</u> = <u>35</u>
5 5
z = 7 plants
There were 7 zucchini plants, 14 (2 x 7) cucumber plants, and 22 (2 x 7 + 8) tomato plants.
Given:
f(x) is an exponential function.
![f(-3.5)=25, f(6)=33](https://tex.z-dn.net/?f=f%28-3.5%29%3D25%2C%20f%286%29%3D33)
To find:
The value of f(6.5).
Solution:
Let the exponential function is
...(i)
Where, a is the initial value and b is the growth factor.
We have,
. So, put x=-3.5 and f(x)=25 in (i).
...(ii)
We have,
. So, put x=6 and f(x)=33 in (i).
...(iii)
On dividing (iii) by (ii), we get
![\dfrac{33}{25}=\dfrac{ab^{6}}{ab^{-3.5}}](https://tex.z-dn.net/?f=%5Cdfrac%7B33%7D%7B25%7D%3D%5Cdfrac%7Bab%5E%7B6%7D%7D%7Bab%5E%7B-3.5%7D%7D)
![1.32=b^{9.5}](https://tex.z-dn.net/?f=1.32%3Db%5E%7B9.5%7D)
![(1.32)^{\frac{1}{9.5}}=b](https://tex.z-dn.net/?f=%281.32%29%5E%7B%5Cfrac%7B1%7D%7B9.5%7D%7D%3Db)
![1.0296556=b](https://tex.z-dn.net/?f=1.0296556%3Db)
![b\approx 1.03](https://tex.z-dn.net/?f=b%5Capprox%201.03)
Putting b=1.03 in (iii), we get
![33=a(1.03)^{6}](https://tex.z-dn.net/?f=33%3Da%281.03%29%5E%7B6%7D)
![33=a(1.194)](https://tex.z-dn.net/?f=33%3Da%281.194%29)
![\dfrac{33}{1.194}=a](https://tex.z-dn.net/?f=%5Cdfrac%7B33%7D%7B1.194%7D%3Da)
![a\approx 27.63](https://tex.z-dn.net/?f=a%5Capprox%2027.63)
Putting a=27.63 and b=1.03 in (i), we get
![f(x)=27.63(1.03)^x](https://tex.z-dn.net/?f=f%28x%29%3D27.63%281.03%29%5Ex)
Therefore, the required exponential function is
.