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The answer is: <u>2(k2−4k)(2c+5)</u>
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Step:
* Consider 2ck2+5k2−8ck−20k. Do the grouping 2ck2+5k2−8ck−20k=(2ck2+5k2) +(−8ck−20k), and factor out k2 in the first and −4k in the second group.
* Factor out the common term 2c+5 by using the distributive property.
* Rewrite the complete factored expression.
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Answer:
6 units
Step-by-step explanation:
Answer:
1) -0.669
2) -0.669
3) 0.669
Step-by-step explanation:
Since we are subtracting or adding multipled of pi, we will either obtain 0.669 or -0.669 as our answer for each of the three different questions.
Cosine is the x-coordinate in our orderes pairs. If our point ends up on the right side of the y-axis, the cosine will be positive. If our point ends up on left side, it will be negative.
Choose a thetha (I'm going to choose it in degrees) in the first quadrant to help with a visual.
If theta=70:
1) then 180-70=110 which is in second quadrant, so our cosines will be opposite in value.
2) then 180+70=250 which is in third quadrant, so our cosines will be opposite in value.
3) then 4×180-70=720-70=650 =1(360)+290 which ends up in the 4th quadrant which means the consines will have the same value.
The answer is y = -5/7x + 4/7! The first step is to subtract the 5x so it’s on the other side of the equal sign. So now the equation is 7y = -5x + 4. Then divide each of them for 7
2.) dT/dt = -t^2 + 3t
dT = (-t^2 + 3t)dt
T = -t^3/3 + 3t^2/2 + C
at 4:00 AM
80 = -4^3/3 + 3*4^2/2 + C
C = 80 + 4^3/3 - 3*4^2/2
C = 77.33
T = -t^3/3 + 3t^2/2 + 77.33
at 8:00 AM
T = -8^3/3 + 3*8^2/2 + 77.33
T = 2.67 deg
