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Korvikt [17]
3 years ago
13

.

Mathematics
1 answer:
Alex787 [66]3 years ago
4 0

Answer:

do the remaining part

Step-by-step explanation:

mark me as brainliest

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6-12.

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What is the risk of going into a group of more than 20 or more people at this time from coronavirus?
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Even if a person doesn't show symptoms, they can still have it.

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Read 2 more answers
Out of six computer chips, two are defective. If two chips are randomly chosen for testing (without replacement), compute the pr
Ratling [72]

Answer:

The probability that of the two chips selected both are defective is 0.1089.

Step-by-step explanation:

Let <em>X</em> = number of defective chips.

It is provided that there are 2 defective chips among 6 chips.

The probability of selecting a defective chip is:

P(X)=p=\frac{2}{6}=0.33

A sample of <em>n</em> = 2 chips are selected.

The random variable <em>X</em> follows a Binomial distribution with parameter <em>n</em> = 2 and <em>p</em> = 0.33.

The probability function of a Binomial distribution is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0, 1, 2, ...

Compute the probability that of the two chips selected both are defective as follows:

P(X=2)={2\choose 2}(0.33)^{2}(1-0.33)^{2-2}=1\times 0.1089\times 1=0.1089

Thus, the probability that of the two chips selected both are defective is 0.1089.

The sample space of selecting two chips is:

S = (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)

     (2, 1),  (2, 3), (2, 4), (2, 5), (2, 6)

     (3, 1), (3, 2), (3, 4), (3, 5), (3, 6)

     (4, 1), (4, 2), (4, 3), (4, 5), (4, 6)

     (5, 1), (5, 2), (5, 3), (5, 4), (5, 6)

     (6, 1), (6, 2), (6, 3), (6, 4), (6, 5)

3 0
3 years ago
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