Here is the problem.....√(15x + 10) = 2x+3
to remove the square root, we do the opposite which is to square everything.
(√(15x + 10))² = (2x + 3)² (the square negates the square root)
15x + 10 = (2x +3)(2x + 3) (use the distributive property to continue)
15x + 10 = 4x² + 6x + 6x + 9 (combine like terms)
15x + 10 = 4x² + 12x + 9 (subtract 15x and 10 from each side)
-15x - 10 -15x - 10
0 = 4x² - 3x - 1 (factor completely)
(x - 1) (4x + 1) (set each to equal 0)
x - 1 = 0 4x + 1 = 0
x = 1 4x = -1
x = -1/4
place both into the equation to check for reasonableness...we see the negative number is not reasonable, but the x value of 1 is a solution.
answer is 1
Answer:
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Step-by-step explanation:
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The answer is no. Because solution (a,b) means x=a, y=b.and we have a-b=5. And (b,a) would mean x=b and y=a but then x-y=b-a=-(a-b)=-5≠5. So the pair (b,a) is not a solution.
Answer:
18cm
Step-by-step explanation:
