For question 1, the formula for that is m1= 1/2(a-b). 106 being A and 62 being B. You should get m1=.5*(106-62) which equals B.22
if we zero out f(x), namely make y = 0, we can get the roots or x-intercepts for this quadratic equation

now, the equation is in x-terms, meaning is a vertically opening parabola, so the axis of symmetry will be x = something, a vertical line.
well, we have two x-intercepts, one at -4 and another at 2, and the vertex is right half-way between those guys
-4------------(-1)------------2
so the vertex is at x=-1, namely the axis of symmetry is x = -1.
Answer:
(-3, 9)
Step-by-step explanation:
If a point was reflected across the y-axis, then the y-coordinate would change signs (from negative to positive or from positive to negative). Using this, we could find the original point by changing the sign of the y-coordinate. As you may already see, this is really just reflecting the point across the y-axis again. By doing this, you get the point (-3, 9).
The point would be (-3, 9).
I hope this helps. :)
The pH of the weak acid is 3.21
Butyric acid is known as a weak acid, we need the concentration of [H+] formula of weak acid which is given by this equation :
![[H^{+}]=\sqrt{Ka . Ma}](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%3D%5Csqrt%7BKa%20.%20Ma%7D)
where [H+] is the concentration of ion H+, Ka is the weak acid ionization constant, and Ma is the acid concentration.
Since we know the concentration of H+, the pH can be calculated by using
pH = -log[H+]
From question above, we know that :
Ma = 0.0250M
Ka = 1.5 x 10¯⁵
By using the equation, we can determine the concentration of [H+]
[H+] = √(Ka . Ma)
[H+] = √(1.5 x 10¯⁵ . 0.0250)
[H+] = 6.12 x 10¯⁴ M
Substituting the value of [H+] to get the pH
pH = -log[H+]
pH = -log(6.12 x 10¯⁴)
pH = 3.21
Hence, the pH of the weak acid c3h7cooh is 3.21
Find more on pH at: brainly.com/question/14466719
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