The answer is D. No solution
Work: |-2x-1|=-11
The standard deviation of the sampled containers' contents is 0.36
<h3>How to determine the mean</h3>
- Data = 20.72, 20.6, 20.71, 20.92, 19.79, 20.93, 20.09, 20.27, 20.49, 20.2
- Number of data (n) = 10
- Summation of data = 20.72 + 20.6 + 20.71 + 20.92 + 19.79 + 20.93 + 20.09 + 20.27 + 20.49 + 20.2 = 204.72
- Mean (μ) =?
Mean = summation of data / number
μ = 204.72 / 10
μ = 20.472
<h3>How to determine the standard deviation</h3>
- Data = 20.72, 20.6, 20.71, 20.92, 19.79, 20.93, 20.09, 20.27, 20.49, 20.2
- Number of data (n) = 10
- Mean (μ) = 20.472
- Standard deviation (σ) =?
σ = √[[(x₁ - μ)² + (x₂ - μ)² + (x₃ - μ)² + (x₄ - μ)² + (x₅ - μ)² + (x₆ - μ)² + (x₇ - μ)² + (x₈ - μ)² + (x₉ - μ)² + (x₁₀ - μ)²] / n]
σ = √[[(20.72 - 20.472)² + (20.6 - 20.472)² + (20.71 - 20.472)² + (20.92 - 20.472)² + (19.79 - 20.472)² + (20.93 - 20.472)² + (20.09 - 20.472)² + (20.27 - 20.472)² + (20.49 - 20.472)² + (20.2 - 20.472)²] / 10]
σ = 0.36
Learn more about statistics:
brainly.com/question/8974461
#SPJ1
To determine the answer, we need to set up equations. We do this by doing mass balances. We let
x = A alloy 25% copper
y = B alloy 55% copper
Overall Mass balance:
x + y = 100
Copper mass balance:
.25x + .55y = .43(100) = 43
SOlving simultaneously, we get:
x = 99.67 kg 25% copper alloy
y = 0.33 kg 55% copper alloy
Answer:
x^2 - 10x + 29
Step-by-step explanation:
f(g(x)) = (x-5)^2 + 4
= x^2 - 10x + 25 + 4
= x^2 - 10x + 29
Answer:
The amount in Brooke's lunch account change by the end of that week is $-20 or $20 decrease.
Step-by-step explanation:
Consider the provided information.
Each day Brooke buys lunch and withdrawn the same amount i.e $4.
The number of days are 5.
To calculate the change by the end of that week, find the total amount withdrawn in 5 days.
To represent withdrawn use a negative sign.
The product of the numbers will be a negative number as they have opposite sign.
Hence, the amount in Brooke's lunch account change by the end of that week is $-20 or $20 decrease.
