Step-by-step explanation: We can write a ratio using the word "to", using a colon, or using a fraction bar.
Here, since we want our ratio in simplest form,
I would use a fraction bar.
Now, the problem asks us to compare
the number of boys to the number of girls.
We know that there are 12 boys
and we know that there are 15 girls.
So our ratio is 12/15.
However, this can be reduced to 4/5.
I think is yes but I’m not sure
The equation should look like :
[H+] = (1-a)(x) + (a)(y)
Where:
5.8 = -log [H+]
5.0 = -log x
6.9 = -log y
(1-a) = proportion of x
<span>a = proportion of y
so calculating a will give you the result of how many ounces are required</span>
Answer:
xy = 1
k = 79
Step-by-step explanation:
Question One
The first and third frames look to me to be the same. I'll treat them that way.
y = x^2 Equate y = x^2 to the result of 2y + 6 = 2x + 6
2y + 6 = 2(x + 3) Remove the brackets
2y + 6 = 2x + 6 Subtract 6 from both sides
2y = 2x Divide by 2
y = x
Now solve these two equations.
so x^2 = x
x > 0
1 solution is x = 0 from which y = 0. This won't work. x must be greater than 0. So the other is
x(x) = x Divide both sides by x
x = 1
y = x^2 Put x = 1 into x^2
y = 1^2 Solve
y = 1
The second solution is
(1,1)
xy = 1*1
xy = 1
Answer: A
Question Two
square root(k + 2) - x = 0
Subtract x from both sides
sqrt(k + 2) = x Square both sides
k + 2 = x^2 Let x = 9
k + 2 = 9^2 Square 9
k + 2 = 81
k = 81 - 2
k = 79
