Answer:
Step-by-step explanation:
im passing this concept trust me the answer is 12
Given:
m/n-3(m+n)
m=-10 and n=-2
Solving:
-10/-2-3(-10-2) Since m=-10 and n=-2, we substitute them in for the values since they have an equal relationship.
Now, follow Orders of Operations: PEMDAS
-10/-2-3(-12) Simplify parentheses (P)
There are no Exponents (E)
Multiplication (M) and Division (D) are =, so we do whatever operation comes from the left to right.
-10/-2=5 Division comes first on the left.
therefore:
5-3(-12)
-3(12)=-36, Multiplication is last on the right.
therefore:
5-36
5-36=-31 After M/D, we do Addition and Subtraction, which are also =, so we do them left to right.
Therefore -10/-2-3(-10-2)=-31
Here is my answer. I hope it is helpful.
Answer:
see the attached
Step-by-step explanation:
The total cost of Kaylee's purchases will be the sum of products of the number bought and the cost of the item bought. She wants this total to be at most $20. In math terms, where x and y represent songs and TV episodes, the inequalities describing the scenario are ...
- 1.29x +2.99y ≤ 20
- x ≥ 0
- y ≥ 4
The attached graph shows a plot of this set of inequalities with the feasible region shaded red. The combinations of songs and TV episodes Kaylee can afford are shown by the coordinates of the red dots in the feasible region.
According to the "special," if Kaylee buys 6 songs (and 4 TV episodes), she will get a 7th song free. That is, the "special" means point (6, 4) becomes (7, 4) if there is a 7th song that Kaylee wants.
Answer:
Points A and C are on the unit circle
Step-by-step explanation:
The unit circle is a circle of radius 1, that is, all the points that are inside the circle have the sum of the squares of its coordinates that are at most 1. Here, we have to test this for each option.
In options B and D, the coordinates 13/7 and 4/3, respectively, means that this sum will be larger than 1, and this points will not be on the unit circle. Now we text for options A and C.
A. ( 5/13, 12/13)

Since the sum of the squares is 1, the point is on the unit circle.
C. (1/3, 2/3)

Since the sum of the squares is less than 1, the point is on the unit circle.