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3 years ago

Suppose △JMN≅△KQR .

Mathematics

1 answer:

OverLord2011 [107]3 years ago

6 0

The true statements are ∠M≅∠Q, QK¯¯¯¯¯¯≅MJ¯¯¯¯¯¯ and MN¯¯¯¯¯¯¯≅QR¯¯¯¯¯.

In order to determine these, we need to note that where the letter is listed in the original statement determines its congruency. Because they are both first J and K are always the same. This is the same for the ones in the middle (M and Q) and the ones at the end (K and J).

So as an example MN¯¯¯¯¯¯¯≅QR¯¯¯¯¯ is true because MN involves the middle and then first term. QR does the same and is therefore congruent.

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dusya [7]

Answer:

Carlos and Pamela drove 120 miles on the first day, 240 miles on the second day, and 290 miles on the third day.

Step-by-step explanation:

Let x be the number of miles driven on the first day.

Then they drove twice as many miles, or 2x on the second day

and 50 miles more than the second day's, so 2x + 50

The total is 650 across all three days, so we'll take the sum.

x + 2x + (2x + 50) = 650

Combine like terms on the left

5x + 50 = 650

Subtract 50 on both sides

5x = 600

Divide by 5 on both sides

x = 120

Check work:

120 + 2(120) + 2(120) + 50 = 650

120 + 240 + 240 + 50 = 650

600 + 50 = 650

650 = 650

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and 2*120 + 50 = 240 + 50 = 290 miles on the third day

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erastovalidia [21]

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Answer:

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Step-by-step explanation:

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Dahasolnce [82]

Answer:

a) $x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$ , $x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$ , b) $x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$ , $x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$

Step-by-step explanation:

a) The equation must be rearranged into a form with one fundamental trigonometric function first:

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$x = \sin^{-1} \frac{\sqrt{3}}{2}$

Value of x is contained in the following sets of solutions:

$x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$

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b) The equation must be simplified first:

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Value of x is contained in the following sets of solutions:

$x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$

$x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$

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3 years ago

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fomenos

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Download docx

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