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iren2701 [21]
3 years ago
9

Suppose you put $500 into a bank account today. interest is paid annually and the annual interest rate is 8 percent. the future

value of the $500 after 2 years is
Mathematics
1 answer:
Natalka [10]3 years ago
7 0
I think it might be 583.2
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Does a rotation preserve congruence
luda_lava [24]
No (random words to reach 20 characters lol)

7 0
3 years ago
1 HOUR TIME LIMIT
irina1246 [14]

Answer:

Your answer is 1500 foot pounds.

I hope this helps!

Step-by-step explanation:

Edg 2020

3 0
3 years ago
Read 2 more answers
Please please help me out with this problem
Hatshy [7]

Answer:

y = 3x - 4

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, - 4) and (x₂, y₂ ) = (2, 2) ← 2 points on the line

m = \frac{2+4}{2-0} = \frac{6}{2} = 3

Note the line crosses the y- axis at (0, - 4) ⇒ c = - 4

y = 3x - 4 ← equation of line

6 0
3 years ago
A private opinion poll is conducted for a politician to determine what proportion of the population favors adding more national
Ksju [112]

Answer:

n≅376

So sample size is 376.

Step-by-step explanation:

The formula we are going to use is:

n=pq(\frac{z_{\alpha/2}}{E})^{2}

where:

n is the sample size

p is the probability of favor

q is the probability of not in favor

E is the Margin of error

z is the distribution

α=1-0.98=0.02

α/2=0.01

From cumulative standard Normal Distribution

z_{\alpha/2}=2.326

p is taken 0.5 for least biased estimate, q=1-p=0.5

n=0.5*0.5(\frac{2.326}{0.06})^{2}\\n=375.71

n≅376

So sample size is 376

4 0
4 years ago
A tank has the shape of an inverted circular cone (point at the bottom) with height 10 feet and radius 4 feet. The tank is full
german

Answer:

Step-by-step explanation:

Given that tank has the shape of inverted circular cone

Height = 10 feet and radius =  4 feet

After water pumped out height = 5 ft

Hence volume of water pumped out = \frac{1}{3} \pi R^2 h-\frac{1}{3} \pi r^2 h'

Here we have r/h is constant always

Hence \frac{r}{h'} =\frac{R}{h} \\r=Rh'/h = 4(5)/10 = 2

Substitute to get volume of water pumped out = \frac{1}{3} \pi (10*16-4*5)=\frac{140\pi}{3}

Mass of water = density x volume = 62.4(\frac{140\pi}{3})\\= 2912\pi lbs

Work done = force x displacement

= mass x accen x displacement

Here acceleration = gravity = 32.2 ft/sec^2

Displaement = height reduced = 5 ft

W=2912(32.2)(5)\pi =468832\pi foot -pound

6 0
3 years ago
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