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Gnom [1K]
3 years ago
15

A polygon has the following coordinates: A(-4,4), B(-1,1), C(-6,1). Find the length of BC.

Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
7 0

Answer:

5

Step-by-step explanation:

|BC|=\sqrt{(X_c-X_b)^2+(Y_c-Y_b)^2} =\sqrt{25+0} =5.

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Jacob earned 300 on an amount deposited into his bank account for 3 years at a 2% annual simple interest rate how much did Joe d
vampirchik [111]
Joe deposited 180.

300 x .02 x 3 = 180
3 0
3 years ago
A bicycle lock requires a two-digit code of numbers 1 through 9, and any digit may be used only once. Which expression would det
sweet-ann [11.9K]
The answer is the first choice.

P(both even) = (4P1)(3P1) / 9P2
5 0
4 years ago
Read 2 more answers
How do I solve these questions? <br> 5(1+9v)<br> 20b+12<br> -9/4r=-9/2
MatroZZZ [7]
5(1+9v) = 5+ 45v
20b+12= 4(5b+3)
And the last one is r=2
Hope this helps!
7 0
3 years ago
Sam buys
mariarad [96]

Answer:

no

Step-by-step explanation:

2 boxes of eggs = 1.30 × 2 = 2.60

1 bottle of juice = 2.60

he payed 10 and got 0.90 so he payed 9.10

9.10-2.60-2.60= 3.90 which is the price of the 3 baguettes so.... 3.90÷3= 1.30£ is the price for 1 baguette

3 0
3 years ago
Let E = {(x, y) e R2|xy &gt; 0}. Determine whether E is a subspace of R2 . X3
gayaneshka [121]

Answer:

E is not a subspace of \mathbb{R}^2

Step-by-step explanation:

E is not a subspace of  \mathbb{R}^2

In order to see this, we must find two points (a,b), (c,d) in  E such that (a,b) + (c,d) is not in E.

Consider

(a,b) = (1,1)

(c,d) = (-1,-1)

It is easy to see that both (a,b) and (c,d) are in E since 1*1>0 and (1-)*(-1)>0.  

But (a,b) + (c,d) = (1-1, 1-1) = (0,0)

and (0,0) is not in E.

By the way, it can be proved that in any vector space all sub spaces must have the vector zero.

5 0
3 years ago
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