First we have to see in both cases what is the cost of one ticket
in the fist case 12.5/5=2.5
in the second case 20.16/8=2.52
therefore 5 tickets for 12.5 is the better deal
Answer:
<u>There are 18 girls in a group that has 16 boys.</u>
Step-by-step explanation:
1. Let's review the information given to us for solving the question:
Number of girls in the grade = 81
Number of the boys in the grade = 72
Number of students in the grade = 81 + 72 = 153
2. Let's find the number of girls in a group that has 16 boys.
For getting that number we will use the Rule of three simple, this way:
Number of girls in a group that has 16 boys = (81 * 16)/72
Number of girls in a group that has 16 boys = 1,296 / 72
<u>Number of girls in a group that has 16 boys = 18</u>
<u>There are 18 girls in a group that has 16 boys.</u>
Answer:
40 ft²
Step-by-step explanation:
The shape of the outdoor carpet can be decomposed into 2 triangles and 1 rectangle
✔️Area of triangle 1:
Area = ½*bh
b = 6 - 3 = 3 ft
h = 11 - 7 = 4 ft
Area of triangle 1 = ½*3*4 = 6 ft²
✔️Area of triangle 2:
Area = ½*by
b = 2 ft
h = 3 ft
Area of triangle 2 = ½*2*3 = 3 ft
✔️Area of rectangle = L × W
L = 11 ft
W = 3 ft
Area of rectangle = 11 × 3 = 33 ft
✅area of outdoor carpet = 4 + 3 + 33 = 40 ft²
Answer:
{24, 18, 12, 6, 0} is the range of the above function
Step-by-step explanation:
solution:
let, x= -4
f(-2) = 12-3*(-2)
= 12+12
=24
let,x= -2
f(-2) = 12-3*(-2)
=12+6
18
let,x =0
f(0)= 12-3*0
=12-0
=12
let,x=2
f(2) = 12-3*2
=12-6
=6
let,x=4
f(4) = 12-3*4
=12-12
=0
Answer:
When we have a function f(x), the domain of the function is the set of all the inputs that "work" (Not only in a mathematical way, the context is also important) with the function f(x)
In this case, we have a function M(p) = $2*p
This function represents the amount of money collected depending on the number of people who ride on the ferris whell.
Then p can be only a whole number (we can not have 1.5 people, only whole numbers of people).
And we also know that the maximum capacity of the ferris is 64 people.
Then:
p ≤ 64
And we also should add the restriction:
0 ≤ p ≤ 64
(Because p can't be smaller than zero)
Such that p should also be an integer, then, the domain is:
D: p ∈ Z, p ∈ {0, 1, 2, ..., 64}
