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3 years ago

11

Which of the statements below are true for linear functions

2 answers:

Virty [35]3 years ago

8 0

I need a picture to help

Studentka2010 [4]3 years ago

7 0

you need to attach a file we cannot see choices once you do i can help

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Marina walks from the police station at (-10, -4) to her friend Marissa’s house at (3, -8). She stops half way at a fast food re

Volgvan

$\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ -10}}\quad ,&{{ -4}})\quad 
% (c,d)
&({{ 3}}\quad ,&{{ -8}})
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)
\\\\\\
\left( \cfrac{3-10}{2}~~,~~\cfrac{-8-4}{2} \right)$

8 0

3 years ago

Find the distance of the point (3,4) from the midpoint of the line joining (8,10) and (4,6)

Elis [28]

Answer:

Distance between point $(3,4)$ and midpoint of line joining $(8,10)$ and $(4,6)$ = $5$ units.

Step-by-step explanation:

Given:

Points:

$A(3,4)\\B(8,10)\\C(4,6)$

To find distance from point A to midpoint of BC.

Midpoint M of BC:

$M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\\$

$M=(\frac{8+4}{2},\frac{10+6}{2})\\$ [Plugging in points $B(8,10)\ and\ C(4,6)$ ]

$M=(\frac{12}{2},\frac{16}{2})\\$

$M=(6,8)\\$

Distance between A and M:

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\$

$D=\sqrt{(6-3)^2+(8-4)^2} \\$ [Plugging in points $A(3,4)\ and\ M(6,8)$ ]

$D=\sqrt{(3)^2+(4)^2} \\$

$D=\sqrt{9+16} \\$

$D=\sqrt{25} \\$

$D=\pm5$

Since distance is always positive ∴ $D= 5$ units

4 0

3 years ago

Which number line represents the solution to the inequality 125x + 200 > 1,200?

Elza [17]

Answer:

see below

Step-by-step explanation:

25x + 200 > 1,200

Subtract 200 from each side

25x + 200-200 > 1,200-200

25x> 1000

Divide by 25

25x/25 >1000/25

x>40

6 0

3 years ago

What is the answer I'm stuck

igomit [66]

1. 4x-1
3. X+5
5. -20x+30
7. 3x+22

5 0

3 years ago

Read 2 more answers

How do you solve this inequality? 200-15d<80

RSB [31]

1) add 15d to both sides
200<span><80+15d

2) takeaway 80 from both sides
120</span><span><15d

3)divide by 15 to solve the inequality
8</span><span><d</span>

4 0

3 years ago