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blondinia [14]
3 years ago
7

Can you please help meeee

Mathematics
1 answer:
Sidana [21]3 years ago
5 0
3. y=5x+1
y=3x+5
5x+1=3x+5
5x-3x=5-1
2x=4
x=2

4.y=3x-5
3x-2y=4
2y=6x-10
2y=3x-4
6x-10=3x-4
6x-3x=-4+10
3x=6
x=2

5.3x-y=13
2x+3y=16
3x-y=13
2x+3y=16
y=3x-13
3y=16-2x
3y=9x-39
3y=16-2x
9x-39=16-2x
9x+2x=16+39
11x=55
x=11


Hope i helped ❤️
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Two points in the Cartesian plane are A(2.00 m, −4.00 m) and B(−3.00 m, 3.00 m). Find the distance between them and their polar
Brrunno [24]

The distance between the two points is d=8.6m

The polar coordinate of A is \left(4.47,296.57\right)

The polar coordinate of B is \left(4.24,135\right)

Explanation:

The two points are A(2,-4) and B(-3,3)

The distance between two points is given by,

d=\sqrt{(2+3)^{2}+(-4-3)^{2}}\\d=\sqrt{(5)^{2}+(-7)^{2}}\\d=\sqrt{25+49}\\d=8.6

Thus, the distance between the two points is d=8.6m

The polar coordinates of A can be written as (Distance, tan^{-1} \frac{y}{x} )

Distance = \sqrt{x^{2} +y^{2} }

Substituting A(2,-4), we get,

Distance = \sqrt{2^{2} +(-4)^{2} }=\sqrt{4+16 }=4.47

tan^{-1} \frac{y}{x} =tan^{-1} \frac{-4}{2}=-63.43

To make the angle positive, let us add 360,

\theta=360-63.43=296.57

The polar coordinate of A is \left(4.47,296.57\right)

Similarly, The polar coordinate of B can be written as (Distance, tan^{-1} \frac{y}{x} )

Distance = \sqrt{x^{2} +y^{2} }

Substituting B(-3,3), we get,

Distance = \sqrt{(3)^{2}+(3)^{2}}=4.24

tan^{-1} \frac{y}{x} =tan^{-1} \frac{3}{-3}=-45

To make the angle positive, let us add 360,

\theta=180-45=135^{\circ}

The polar coordinate of B is \left(4.24,135\right)

5 0
3 years ago
Combine like terms to create an equivalent expression -1/2(-3y+10)
marysya [2.9K]

Answer:

3/2y - 5

Step-by-step explanation:

-1/2(-3y+10)

Expand the brackets.

-1/2(-3y) -1/2(10)

Multiply.

3/2y - 5

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3 years ago
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alukav5142 [94]
The answer to that question is b
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3 years ago
BC has a midpoint at M(6, 6). Point C is at (2, 10). Find the coordinates of point B.
agasfer [191]

Answer:

The coordinates of B are (10,2)

Step-by-step explanation:

Hi there!

We know that BC has a midpoint M, with the coordinates (6,6), and the endpoint C, with coordinates (2, 10)

We want to find the coordinates of point B

The midpoint formula is (\frac{x_1 + x_2}{2}, \frac{y_1+ y_2}{2}), where (x_1, y_1) and (x_2 , y_2) are points. In this case, the point C has the values of (x_1, y_1), and B has the values of (x_2 , y_2)

We know that coordinates of M equal (\frac{x_1 + x_2}{2}, \frac{y_1+ y_2}{2})

In other words,

\frac{x_1 + x_2}{2} = 6\\ \frac{y_1+ y_2}{2}=6

Let's plug 2 for x_1 and 10 for y_1

So:

\frac{2 + x_2}{2} = 6\\ \frac{10+ y_2}{2}=6

Multiply both sides by 2

{2 + x_2} = 12\\{10+ y_2} =12

Subtract 2 from both sides in the first equation to find the value of x_2:

x_2=10

Now, for the second equation, subtract 10 from both sides to find the value of y_2

y_2=2

Now substitute these values for (x_2, y_2)

(x_2, y_2)=(10,2)

So the coordinates of point B are (10, 2)

Hope this helps!

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