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blagie [28]
3 years ago
11

Question 10 Multiple Choice Worth 1 points)

Mathematics
1 answer:
zheka24 [161]3 years ago
3 0

Answer:

Linearly, because the table shows that the sunflowers increased by the same amount each month

Step-by-step explanation:

Given the table

\begin{array}{lcccc}\text{Month}&1&2&3&4\\ \\\text{Sunflowers}&15&17.2&19.4&21.6\end{array}

Note that months change one-by-one (21-1, 3-2=1, 4-3=1).

Also

17.2-15=2.2\ [\text{from month 1 to month 2}]\\ \\19.4-17.2=2.2\ [\text{from month 2 to month 3}]\\ \\21.6-19.4=2.2\ [\text{from month 3 to month 4}]

This means the number of sunflowers increases linearly, because the table shows that the sunflowers increased by the same amount each month

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1. How many squares do I shade on 10 square grid for 60% of 40 ?
Sholpan [36]

Answer:

Either 2.4 boxes or 6

Step-by-step explanation:

10% of 40 is 4

60% of 40 is 24

Either 2.4 boxes or 6

6 0
3 years ago
Dianne measured the thickness of 1000 sheets of paper as 264mm. How thick is the sheet? Please hurry anyone!!!!!
Karo-lina-s [1.5K]

Answer:

0.264 mm

Step-by-step explanation:

Number of sheets = 1000

Thickness of entire sheet = 264 mm

The thickness of the sheet is :

Thickness of entire sheet / number of sheets

264 mm / 1000

= 0.264 mm

6 0
3 years ago
Some friends plotted the locations of their house on a map. brianna's house is at (1,6), Jordan's house is at (5,3). What is one
Rufina [12.5K]
Let
A (1,6)------> location <span>brianna's house on a map
B </span>(5,3)------> location Jordan's house on a map

we know that
One possible path from brianna's house to jordan's house it's a straight line  ( <span>the shortest distance)</span>

using a graph tool
see the attached figure

find the distance points AB
d=√[(y2-y1)²+(x2-x1)²]-----> d=√[(3-6)²+(5-1)²]----> d=√[3²+4²]
d=√25----> d=25 units

the distance from brianna's house to jordan's house is 25 units

4 0
3 years ago
What is the y-intercept of the line that is
DaniilM [7]

Answer:

The y-intercept of the line would be (C) 8

Step-by-step explanation:

The slope of the line with the equation y = -3x - 5 is -3. When figuring out a slope perpendicular to another line you would use the negative reciprocal of the slope which would lead to the slope of the line to be 1/3.

We know it passes through the point (-3,7), substituting x and y, we would then get our new equation, (7) = \frac{1}{3}( -3) + b.

Solve the equation by multiplying -3 with 1/3 and the product would be -1. Add negative one on both sides and you would get 8 = b.

3 0
3 years ago
Suppose quantity s is a length and quantity t is a time. Suppose the quantities v and a are defined by v = ds/dt and a = dv/dt.
finlep [7]

Answer:

a) v = \frac{[L]}{[T]} = LT^{-1}

b) a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}

c) \int v dt = s(t) = [L]=L

d) \int a dt = v(t) = [L][T]^{-1}=LT^{-1}

e) \frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}

Step-by-step explanation:

Let define some notation:

[L]= represent longitude , [T] =represent time

And we have defined:

s(t) a position function

v = \frac{ds}{dt}

a= \frac{dv}{dt}

Part a

If we do the dimensional analysis for v we got:

v = \frac{[L]}{[T]} = LT^{-1}

Part b

For the acceleration we can use the result obtained from part a and we got:

a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}

Part c

From definition if we do the integral of the velocity respect to t we got the position:

\int v dt = s(t)

And the dimensional analysis for the position is:

\int v dt = s(t) = [L]=L

Part d

The integral for the acceleration respect to the time is the velocity:

\int a dt = v(t)

And the dimensional analysis for the position is:

\int a dt = v(t) = [L][T]^{-1}=LT^{-1}

Part e

If we take the derivate respect to the acceleration and we want to find the dimensional analysis for this case we got:

\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}

7 0
3 years ago
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