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marin [14]
3 years ago
14

Given OR=OQ. prove<3=<5

Mathematics
1 answer:
nadezda [96]3 years ago
4 0

The answer is 0Step-by-step explanation:

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Approximately 80,000 marriages took place in the state of New York last year. Estimate the probabilitythat for at least one of t
lilavasa [31]

Answer:

a. 0.45 b. 1

Step-by-step explanation:

We will be using Poisson Approximation of Binomial because n = 80,000 is large and probability (<em>p) </em>is very small.

We calculate for (a) as follows:

The probability that both partners were born on April 30 is

<em>p </em>= 1/365 X 1/365

<em>p </em>= 1/133,225

<em>p </em>= 0.00000751

Using Poisson Approximation, we have:

λ = n<em>p</em>

λ = 80,000 X 0.00000751

λ = 0.6

We use λ to calculate thus:

P (X \geq 1) = 1 - P ( X = 0)

              = 1 - e^-λ

              = 1 - e^-0.6

              = 0.451

There is a 45.1% probability that, for at least one of these couples, both partners were born on April 30.

(b) To calculate the probability that both partners celebrated their birthday on the same day:

<em>p </em>(same birthday) = 365 X 1/365 X 1/365

                             = 1/365

λ = n<em>p</em>

λ = 80,000 X 1/365

λ = 219.17

P (X \geq 1) = 1 - P ( X = 0)

= 1 - e^-λ

= 1 - e^-219.17

≈ 1

There is almost 100% probability that, for at least one of these couples, both partners celebrate their birthday on the same day of the year.

7 0
3 years ago
Calculate the quotient below and give your answer in scientific notation.<br> 2.64*10^-3\8.0*10^0
Zolol [24]

Answer:

The quotient of: \frac{2.64\cdot 10^{-3}}{8.0\cdot 10^0} is: \mathbf{3.3\times 10^{-4}}

Step-by-step explanation:

We need to find quotient of: \frac{2.64\cdot 10^{-3}}{8.0\cdot 10^0}

We know that 10^0=1

Now solving:

\frac{2.64\cdot 10^{-3}}{8.0\cdot 10^0}\\=\frac{2.64\cdot 10^{-3}}{8.0}\\=\frac{0.00264}{8}\\=0.00033

Writing it in scientific notation

0.00033\\=3.3\times10^{-4}

So, the quotient of: \frac{2.64\cdot 10^{-3}}{8.0\cdot 10^0} is: \mathbf{3.3\times 10^{-4}}

3 0
3 years ago
For the following problem state the objective function and the constraints. DO NOT solve:
Mama L [17]

Answer:

If we define S as the number Sprinkle's umbrellas, and H as the Hurricane's umbrellas, the profit P can be expressed as:

P=3S+5H

The restriction for cloth can be written as:

S+2H\leq500

The restriction for metal can be written as:

2S+3H\leq600

The restriction for wood can be written as:

4S+7H\leq800

The condition for S and H to be positive is:

S, H \geq0

Step-by-step explanation:

We have an objective function that, in this case, we want ot maximize.

This function is the Profit (P).

If we define S as the number Sprinkle's umbrellas, and H as the Hurricane's umbrellas, the profit can be expressed as:

P=3S+5H

We have 3 restrictions, plus the condition that both S and H are positive.

The restriction for cloth can be written as:

S+2H\leq500

The restriction for metal can be written as:

2S+3H\leq600

The restriction for wood can be written as:

4S+7H\leq800

The condition for S and H to be positive is:

S, H \geq0

5 0
3 years ago
Please someone help me please!I'm struggling and I'll give extra point's!
alukav5142 [94]

Answer:

The x variable has an exponent of 2

Step-by-step explanation:

To be a linear equation, the highest power must be 1 on the variables

2x^2 +y =7 is quadratic since x^2 has a power of 2

3 0
3 years ago
What is the relationship between the 6s in the number 660472
kirill115 [55]
It would be sixty six hundred thousand four hundred and seventy-two.
3 0
3 years ago
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