What is the missing number from the following sequence?<br><br> 4 7 11 18 29 47 _

Please help me guys please

madam [21]

parallel when a=2

perpendicular when a=-1/2

3 0

3 years ago

In a hypothesis test, if the computed P-value is greater than a specified level of significance, then we__________.

Verizon [17]

Answer:

We fail to reject the null hypothesis.

Step-by-step explanation:

In a hypothesis test, if the computed p-value is grater than a specified level of significance, then we fail to reject the null hypothesis. The p-value can be computed as the probability of getting a value equal or greater (in absolute value) than the observed value using the test statistic, this implies that if the p-value is greater than a specified level of significance, then the observed value does not fall inside the rejection region. Therefore we fail to reject the null hypothesis.

8 0

3 years ago

On a math test , you scored 69 out of a total of 75 points. what percent did you get ?

Black_prince [1.1K]

Simple, to find the percentage you scored on your test, take

What you got= 69
Total=75

Divide,

69/75=0.92

Finally, multiply by 100.

0.92*100=92

<span>You got a 92% on the math test.</span>

8 0

3 years ago

PLS HELP ME!!! The figure is made up of a cone and a hemisphere. To the nearest whole number, what is the approximate volume of

Pachacha [2.7K]

Hello!

The figure is made up of a cone and a hemisphere. To the nearest whole number, what is the approximate volume of this figure? Use 3.14 to approximate π . Enter your answer in the box. cm³

Data: (Cone)

h (height) = 12 cm

r (radius) = 4 cm (The diameter is 8 being twice the radius)

Adopting: $\pi \approx 3.14$

V (volume) = ?

Solving: (Cone volume)

$V = \dfrac{ \pi *r^2*h}{3}$

$V = \dfrac{ 3.14 *4^2*\diagup\!\!\!\!\!12^4}{\diagup\!\!\!\!3}$

$V = 3.14*16*4$

$\boxed{V = 200.96\:cm^3}$

Note: Now, let's find the volume of a hemisphere.

Data: (hemisphere volume)

V (volume) = ?

r (radius) = 4 cm

Adopting: $\pi \approx 3.14$

If: We know that the volume of a sphere is $V = 4* \pi * \dfrac{r^3}{3}$ , but we have a hemisphere, so the formula will be half the volume of the hemisphere $V = \dfrac{1}{2}* 4* \pi * \dfrac{r^3}{3} \to \boxed{V = 2* \pi * \dfrac{r^3}{3}}$