Giving brsinlist ASAP

Mathematics

1 answer:

pashok25 [27]2 years ago

7 0

Answer:

1. while I was doing the dishes, the parrot sang along with the radio.

2. dangling

Step-by-step explanation:

In the first question, the original question make it seem like the parrot was doing the dishes. In the second question, a dangling modifier is usually found at the beginning of sentences.

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Simplify<br>2x + x + x + 2y x 3y x y

nignag [31]

Answer: 2y^3x4+4x

Step-by-step explanation:

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2 years ago

Mandarinka [93]

Answer: D:{8,-6,2,0}: R:{5,-9,5,-8}

Explanation:
The domain is x and the range is y, so I'll go through each coordinate;
(8,5) domain=8; range=5
(-6,-9) domain=-6; range=-9
(2,5) domain=2; range=5
(0,-8) domain=0; range=-8
So the answer is D:{8,-6,2,0}: R:{5,-9,5,-8}

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3 years ago

An annual pass to the Super Fun theme

MariettaO [177]

Answer:

Step-by-step explanation:

X=4

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3 years ago

write a function g whose graph represents a translation 2 units to the right followed by a horizontal stretch by a factor or 2 o

Alenkinab [10]

$\bf f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}\\\\
f(x)=&{{ A}} \left|{{ B }}x+{{ C}} \right|+{{ D}}
\\\\
--------------------\\\\$

$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the y-axis}$

$\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

with that template in mind, let's see,

$\bf f(x)=|x| \implies \begin{array}{lllccll}
f(x)=&1|&1x&+0|&+0\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}$

so, to shift it to the right by 2 units, simply set C = 2.
to stretch it by 2, set A = 1/2.

the smaller A is, the wider it opens, the larger it is, the more it shrinks.

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3 years ago

Solve<br> x+y= -1<br> x - y = -7<br> using elimination.

Andreas93 [3]

Answer:

(-4, 3)

x = -4, y = 3

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3 years ago