Answer:
The number of viewers Network A expects will watch their show is 1.4 million viewers.
Step-by-step explanation:
The expected value is calculated by multiplying the possible outcomes by the probability of their occurrence and adding the results
Therefore, we have the expected value given by the following expression;
Estimated network A viewers where network B schedule top show = 1.1 million viewers
Estimated network A viewers where network B schedule a different show = 1.6 million viewers
Probability that Network B will air its top show = 0.4
Probability that Network B will air another show = 0.6
We therefore have;
Expected value, E of Network A viewers is therefore;
E = 1.1 × 0.4 + 1.6 × 0.6 = 0.44 + 0.96 = 1.4 million viewers.
Network A expects 1.4 million viewers will watch their show.
Well think of it like this. lets say your teacher made you do this problem -48 - 10. I would just act like 48 is not an negative and add 10. After that I would put the negative back. So the answer would be -58. :P
Answer:
9<7x
Step-by-step explanation:
5(3-x) < -2x+6
15-5x<-2x+6
9<7x
then you can simplify it if you want
Answer:
H0 : μ1 - μ2 = 0
H1 : μ1 - μ2 ≠ 0
-1. 34
0.1837
Step-by-step explanation:
Full time :
n1 = 125
x1 = 2.7386
s1 = 0.65342
Part time :
n2 = 88
x2 = 2.8439
s2 = 0.49241
H0 : μ1 - μ2 = 0
H1 : μ1 - μ2 ≠ 0
Test statistic :
The test statistic :
(x1 - x2) / sqrt[(s1²/n1 + s2²/n2)]
(2.7386 - 2.8439) / sqrt[(0.65342²/125 + 0.49241²/88)]
−0.1053 / sqrt(0.0034156615712 + 0.0027553)
-0.1053 /0.0785554
= - 1.34
Test statistic = - 1.34
The Pvalue :
Using df = smaller n - 1 = 88 - 1 = 87
Pvalue from test statistic score ;
Pvalue = 0.1837
Pvalue > α ; We fail to reject the null and conclude that the GPA does not differ.
At α = 0.01 ; the result is insignificant
I think it is because they are both different differences
