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-Dominant- [34]
2 years ago
8

If a = 31, what is the circumference of the circle? (Round to one decimal place.)

Mathematics
2 answers:
ololo11 [35]2 years ago
8 0

Answer:

The circumference is 194.78, but it's <u>194.8</u> when rounded to the nearest tenth.

The area is <u>3019.1</u>.

Step-by-step explanation:

To find these values, all you have to do is use these formulas.

Area = πr2.

Circumference = 2πr.

Since you already know what r (radius, but it's marked as a on the drawing) is, you can simply plug r (31) into the formulas.

First let's do area.

Area = π(31)²

Do (31)² first before doing anything with π.

(31)² = 961

Now you have:

Area = π(961)

π · 961 = 3019.1

__________________________________________________________

Now for the circumference. Put 31 in place of "r".

C = 2π(31)

Do π(31)

π · 31 = 97.3893722613, but you can shorten that big number if you want, too.

Now you have:

C = 2(97.3893722613)

2 · 97.3893722613 = 194.8

gregori [183]2 years ago
3 0

circumference is 62pi which equals 194.8

area is 31^2pi which equals 3109.1

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Answer:

PQ = √84 = 2√21 in ≈ 9.165 in

Step-by-step explanation:

The base edges AB = 10 in, AC = 17 in, and BC = 21 in

Q ∈ BC and AQ is the altitude of the base.

Let BQ = x in ⇒ CQ = (21 - x) in

ΔAQB a right triangle at Q

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∴ PQ (hypotenuse) = √(PA² + AQ²)

∴ PQ = √[(2√5)² + 8²] = √(20+64) = √84 = 2√21 in ≈ 9.165 in

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