Question

In ΔSTU, s = 6.1 cm, t = 3.2 cm and u=7.4 cm. Find the measure of ∠S to the nearest 10th of a degree.

Answer 1

Answer:

m∠S = 54.1°

Step-by-step explanation:

Use the law of cosines

$s^{2} = t^{2} + u^{2} - 2utcos S\\6.1^{2} = 3.2^{2} + 7.4^{2} - 2(3.2)(7.4) cos S$

37.21 = 10.24 + 54.76 - 47.36 cos S

-27.79 = -47.36 cos S

.586782 = cos S

arccos .586782 = S

m∠S = 54.1°

Answer 2

Answer:

54.1°

Step-by-step explanation: