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3 years ago

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You may believe that the gender of a salesperson influences the sales of cars. The best way to incorporate this predictor is by

Group of answer choices
a. None of these answers are correct.
b. Using a single dummy variable in a regression model
c. Running two separate regressions, one for females and one for males.
d. Using two dummy variables in a regression model

1 answer:

Burka [1]3 years ago

4 0

Answer: The correct option is (b)

Using a single dummy variable in a regression model

Step-by-step explanation:

A regression model is a model that measures the relationship between a dependent variable and one or more independent variables. In this question the dependent variable y is the sales of the car and the independent variable is the choice of the gender of a salesperson, Which is single dummy variable.

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State if the function is a growth or decay and the factor <br><br> y=2x

Jet001 [13]

Answer:

the function shows growth of a factor of 2

Step-by-step explanation:

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3 years ago

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Assume the probability of having a boy or a girl is the same. What is the probability a family has three boys?

almond37 [142]

The probability of having a boy: 1/2

1/2(1/2)(1/2)=1/8

The probability of a family having three boys is 1/8.

Hope this helps!

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3 years ago

At a hot-air balloon event, a person has to toss a small beanbag from a hot-air balloon onto a target on the ground. The locatio

VLD [36.1K]

40 yards I think please tell me if im wrong!

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3 years ago

Which of the following is a solution

nordsb [41]

$\small\boxed{\begin{array}{cc} \hline\sf \normalsize {Math \: \: \: Question}\\ \hline\end{array}}$

=================================

Which of the following is a solution

to the linear function y = 4/5 x + 7?

A (0,1)

<u>C (-5,11)</u>

B (15,19)

D (-2,1)

=================================

$\begin{gathered}\begin{gathered}\tiny\boxed{\begin{array} {} \red{\bowtie}\:\:\:\: \red{\bowtie}\\｡◕‿◕｡\end{array}}\end{gathered}\end{gathered}$ :BrainliestBunch

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3 years ago

A physical therapist wants to determine the difference in the proportion of men and women who participate in regular sustained p

Alekssandra [29.7K]

Using the z-distribution and the formula for the margin of error, it is found that:

a) A sample size of 54 is needed.

b) A sample size of 752 is needed.

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which z is the z-score that has a p-value of $\frac{1+\alpha}{2}$ .

The margin of error is of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

90% confidence level, hence $\alpha = 0.9$ , z is the value of Z that has a p-value of $\frac{1+0.9}{2} = 0.95$ , so $z = 1.645$ .

Item a:

The estimate is $\pi = 0.213 - 0.195 = 0.018$ .

The sample size is <u>n for which M = 0.03</u>, hence:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.03 = 1.645\sqrt{\frac{0.018(0.982)}{n}}$

$0.03\sqrt{n} = 1.645\sqrt{0.018(0.982)}$

$\sqrt{n} = \frac{1.645\sqrt{0.018(0.982)}}{0.03}$

$(\sqrt{n})^2 = \left(\frac{1.645\sqrt{0.018(0.982)}}{0.03}\right)^2$

$n = 53.1$

Rounding up, a sample size of 54 is needed.

Item b:

No prior estimate, hence $\pi = 0.05$

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.03 = 1.645\sqrt{\frac{0.5(0.5)}{n}}$

$0.03\sqrt{n} = 1.645\sqrt{0.5(0.5)}$

$\sqrt{n} = \frac{1.645\sqrt{0.5(0.5)}}{0.03}$

$(\sqrt{n})^2 = \left(\frac{1.645\sqrt{0.5(0.5)}}{0.03}\right)^2$

$n = 751.7$

Rounding up, a sample of 752 should be taken.

A similar problem is given at brainly.com/question/25694087

5 0

2 years ago