Here I drew one to show an example
I hope this helps
Answer:
exactly one, 0's, triangular matrix, product and 1.
Step-by-step explanation:
So, let us first fill in the gap in the question below. Note that the capitalized words are the words to be filled in the gap and the ones in brackets too.
"An elementary ntimesn scaling matrix with k on the diagonal is the same as the ntimesn identity matrix with EXACTLY ONE of the (0's) replaced with some number k. This means it is TRIANGULAR MATRIX, and so its determinant is the PRODUCT of its diagonal entries. Thus, the determinant of an elementary scaling matrix with k on the diagonal is (1).
Here, one of the zeros in the identity matrix will surely be replaced by one. That is to say, the determinants = 1 × 1 × 1 => 1. Thus, it is a a triangular matrix.
Answer:
I cant see that, its upside down.
Step-by-step explanation:
Answer:
It should be $12168.75
Step-by-step explanation:
First, converting R percent to r a decimal
r = R/100 = 4.25%/100 = 0.0425 per year,
then, solving our equation
I = 11000 × 0.0425 × 2.5 = 1168.75
I = $ 1,168.75
The simple interest accumulated
on a principal of $ 11,000.00
at a rate of 4.25% per year
for 2.5 years is $ 1,168.75.
1,168.75 + 11000 = 12168.75
-12/4= -3
18/5= 3.6
-2.5= -2.5
1/5= .2
10= 10
Ordered) -12/4, -2.5, 1/5, -2.5, 10
The median is 1/5 since it's in the middle of all five numbers.
Hope I could help! :)
