Question

The modulus of elasticity for a ceramic material having 4.7 vol% porosity is 317 GPa. (a) Calculate the modulus of elasticity (in GPa) for the nonporous material.

Answer 1

Answer:

The answer is below

Explanation:

a) Given that the modulus of elasticity (E) = 317 GPa, to find the modulus of elasticity (in GPa) for the nonporous material ($E_o$), we use the formula:

$E_0=\frac{E}{1-1.9P+0.9P^2}\\\\where\ P=4.7\%=0.047,hence:\\\\ E_0=\frac{317}{1-1.9(0.047)+0.9(0.047)^2}\\\\E_0=347.3\ GPa$

b) If the porosity P = 11.1%, then the modulus of elasticity is:

$E=E_0(1-1.9P+0.9P^2)=347.3(1-1.9(0.111)+0.9(0.111)^2)=278\ GPa$