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Georgia [21]
3 years ago
15

Si se deja caer una piedra desde un helicóptero en reposo, entonces al cabo de 20 s cual será la rapidez y la distancia recorrid

a por la piedra
Physics
1 answer:
ahrayia [7]3 years ago
4 0

Answer:

La piedra alcanza una rapidez de 196.14 metros por segundo y una distancia recorrida de 1961.4 metros en 20 segundos.

Explanation:

Si se excluye los efectos del arrastre por la viscosidad del aire, la piedra experimenta un movimiento de caída libre, es decir, que la piedra es acelerada por la gravedad terrestre. La distancia recorrida y la rapidez final de la piedra pueden obtenerse con la ayuda de las siguientes ecuaciones cinemáticas:

v = v_{o} + g\cdot t

y - y_{o} = v_{o}\cdot t + \frac{1}{2}\cdot g \cdot t^{2}

Donde:

v, v_{o} - Rapideces final e inicial de la piedra, medidas en metros por segundo.

t - Tiempo, medido en segundos.

g - Aceleración gravitacional, medida en metros por segundo al cuadrado.

y. y_{o} - Posiciones final e inicial de la piedra, medidos en metros.

Si v_{o} = 0\,\frac{m}{s}, g = -9.807\,\frac{m}{s^{2}}, y_{o} = 0\,m, entonces:

v = 0\,\frac{m}{s} +\left(-9.807\,\frac{m}{s^{2}} \right) \cdot (20\,s)

v = -196.14\,\frac{m}{s}

y-y_{o} = \left(0\,\frac{m}{s} \right)\cdot (20\,s) + \frac{1}{2}\cdot \left(-9.807\,\frac{m}{s^{2}} \right) \cdot (20\,s)^{2}

y-y_{o} = -1961.4\,m

La piedra alcanza una rapidez de 196.14 metros por segundo y una distancia recorrida de 1961.4 metros en 20 segundos.

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