Answer
given,
F₁ is horizontal = 40 N
F₂ is normal = 20 N
F₃ is parallel = 30 N
work done by
W₂ = 0 as force is acting perpendicular to the direction of motion.
as the motion moved to 0.8 cm
W₃ = F₃ x d
W₃ = 30 x 0.8
W₃ = 24 J
W₁ = F₁ x d
W₁ = F₁ cos ∅ x d
W₁ = 40 cos 30⁰ x 0.8
W₁ = 27.21 J
Answer:
the location of the center of gravity for the entire body is 1.08 m
Explanation:
Given the data in the question;
w1 = 458 N, y1 = 1.34 m
w2 = 120 N, y2 = 0.766 m
w3 = 89.8 N, y2 = 0.204 m
The location arrangement of the body part is vertical, locate the overall centre of gravity by simply replacing the horizontal position x by the vertical position y as measured relative to the floor.
so,
= (w1y1 + w2y2 + w3y3 ) / ( w1 + w2 + w3 )
so we substitute in our values
= (458×1.34 + 120×0.766 + 89.8×0.204 ) / ( 458 + 120 + 89.8 )
= 723.9592 / 667.8
= 1.08 m
Therefore, the location of the center of gravity for the entire body is 1.08 m
The answer is Conduction: the process of heat is directly transmitted through a substance when there is a difference in temperature.
Answer:
option C
Explanation:
Let mass of the bullet be m and velocity be v
mass of gun be M and bullet be V
now,
using conservation of momentum for gun 1
(M+m) V' = 2 mv + 3 MV
V' = 0
3 M V = - 2 mv
momentum of gun 1 =- 2 mv---------(1)
now for gun 2
(M+m) V' = mv + MV
V' = 0
M V = - mv
momentum of gun 1 = -mv-----------(2)
dividing equation (1) by (2)


the correct answer is option C