Answer:
B) x^2+6x+8
Explanation:
x-4 | x^3+2x^2-16x-32
- x^3-4x^2 <-- (x-4)(x^2)
_________________
6x^2-16x-32
- 6x^2-24x <-- (x-4)(6x)
_________________
8x-32
- 8x-32 <- (x-4)(8)
___________________________
0 | x^2+6x+8
This means the answer is B) x^2+6x+8
Answer:
VR = 
Explanation:
A machine is a device that can be used to overcome a load by the application of an effort through a pivot. Examples are: pulleys, wedge, screw jack, wheel and axle etc.
The wheel and axle is a simple device that can be used to lift a load through a height. Its velocity ratio (VR) can be determined by:
VR = 
Note that for a practical wheel and axle, the radius of the wheel is greater than the radius of the axle.
Answer:
B) 12 m
Explanation:
Gravitational potential energy is:
PE = mgh
Given PE = 5997.6 J, and m = 51 kg:
5997.6 J = (51 kg) (9.8 m/s²) h
h = 12 m
<h3><u>Given</u> :</h3>
Three identical resistors of resistances 5Ω, 10Ω and 30Ω are connected with a battery of 12V
<h3><u>To Find</u> :</h3>
We have to find current through the each resistor and equivalent resistance of circuit
<h3><u>SoluTion</u> :</h3>
➝ Equivalent resistance of series connection is given by
➝ We know that, Equal current flow through each resistor in series connection.
➝ As per ohm's law, Current flow through a conductor is directly proportional to the applied potential difference.
◈ <u>Equivalent resistance</u> :
⇒ Req = R1 + R2 + R3
⇒ Req = 5 + 10 + 30
⇒ <u>Req = 45Ω</u>
◈ <u>Current flow in circuit</u> :
⇒ V = IReq
⇒ 12 = I × 45
⇒ <u>I = 0.27A</u>
፨ Therefore, 0.27A current will flow through each resistor.