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tankabanditka [31]
3 years ago
6

how does electrical current change when more devices are added to a series circuit? To a parallel circuit?

Physics
1 answer:
Elenna [48]3 years ago
7 0

the intensity at a series circuit is equal everywhere, and on a parallel circuit the total intensity is equal to the sum of the intensities on each ram

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in many compounds, atoms of main-group elements form ions so that the number in the outermost energy levels of each ion is
Tom [10]
I think the answer is 8 it may be right I hope this helps
7 0
3 years ago
Which material is more closely related to the styrofoam? a. heat exchanger b. diffuser c. insulator d. electrical conductor
nirvana33 [79]

The material that is more closely related to the Styrofoam insulator.

Styrofoam is the term that is used for polystyrene foam in a trademark form. It is a petroleum-based plastic.

Keeping something warm includes the stopping of the transfer of heat from one object to another. This is how insulation works.

Styrofoam is an insulator, which means it'll help keep the heat from the environment out of your cooler. However, you'll still need cooling agents (like ice packs) to make the cooler cold in the first place.

Styrofoam is usually made mostly of air, which means it is a poor conductor of heat, but an excellent convector. It traps the air in small pockets, which blocks the flow of heat energy. This reduces both conduction and convection and makes Styrofoam a good insulator.

To learn more about Styrofoam here

brainly.com/question/21369568

#SPJ4

8 0
2 years ago
A ray of monochromatic light ( f = 5.09 × 10^14 Hz) passes from air into Lucite at an angle
harina [27]
     Let us consider the air with the index 1 and the lucite with index 2. Using the Snell's Secound Law, we have:

\frac{sen\O_{2}}{sen\O_{1}} = \frac{n_{2}}{n_{1}} \\ sen\O_{2}= \frac{n_{2}*sen\O_{1}}{n_{1}}
 
     Entering the unknowns, remembering that the air refrective index is 1 and the lucite refrective index is 1.5, comes:

sen\O_{2}= \frac{n_{2}*sen\O_{1}}{n_{1}} \\ sen\O_{2}= \frac{1.5* \frac{1}{2} }{1} \\ sen\O_{2}=0.75
  
     Using the arcsin properties, we get:

sen\O_{2}=0.75 \\ arcsin(0.75)=\O_{2} \\ \boxed {\O_{2}=48.59^o}

Obs: Approximate results, and the drawing is attached

If you notice any mistake in my english, let me know, because i am not native.

6 0
3 years ago
What is the relationship between electric field lines and equipotential lines that you observed in doing the lab
lidiya [134]

Answer:

Explained below

Explanation:

Generally speaking, we know in physics that Electric field lines are lines which usually start at positive charges and deflect away from them to terminate at the negative charges. Meanwhile Equipotential lines are lines that are used to connect points located on the same electric potential.

Finally, in conclusion, electric field lines are usually lines that go through in a perpendicular manner across every equipotential lines.

8 0
3 years ago
Metal sphere A has a charge of -2 units and an identical sphere B has a charge of -4 units. If the spheres are brought into cont
shusha [124]

Answer:

 q1 = q₂=  -3

therefore each sphere has the same charge of -3 untis

Explanation:

The metallic spheres have mobile charge, so when the two spheres come into contact the total charge

           Q_total = q₁ + q₂

           Q_total = -2 -4

   

          Q_total = -6 units

it is distributed in between the two spheres evenly since the charges of the same sign repel each other.

When the spheres separate each one has

            q₁ = -6/2

            q1 = q₂=  -3

therefore each sphere has the same charge of -3 untis

5 0
3 years ago
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