The answer:
we observe that <span>m∠DBC = 130°
</span><span>
we should find the value of </span>mEDB to answer this question
Angle ABC is a straight angle, so m ABC= 180°, but
mABD + <span>m∠DBC = 180° (look at the figure)
</span>
so mABD= 180° - m∠DBC = 180 - 130 = 50°
therefore, mABD= 50°,
and BE bisects ∠ABD imiplies mEBA = mEDB, and mABD= mEBA + mEDB= 50°, it does mean 2x mEBA = 50°
and from where mEBA = 50°/2=25°
Answer:
X= 62°
Step-by-step explanation:
Remember a straight line is 180°. If we were to try to find x, we would have to subtract 180 by 118. If we do that then we get 62°. And I think there corresponding angles.
BTW, I'M VERY SORRY IF MY ANSWER IS WRONG!! I HAVEN'T DONE THIS IN A YEAR!!! Use this as an example, or sum!!! Good luck.
The product of the given two matrices comes out to be ![\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%5C%5C0%261%5Cend%7Barray%7D%5Cright%5D)
Here we are given the 2 matrices as follows-
![\left[\begin{array}{ccc}7&-2\\-6&2\end{array}\right] \left[\begin{array}{ccc}1&1\\3&3.5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D7%26-2%5C%5C-6%262%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%261%5C%5C3%263.5%5Cend%7Barray%7D%5Cright%5D)
To find the product of 2 matrices, the number of columns in the first matrix must be equal to the number of rows in the second matrix.
Here since both of the matrices are 2 × 2, their product is possible.
Now, to find the product, we need to multiply each element in the first row by each element of the 1st column of the second matrix and then find their sum. Similarly, we do this for all rows and columns.
Therefore,
![\left[\begin{array}{ccc}(7*1)+(-2*3)&(7*1)+(-2*3.5)\\(-6*1)+(2*3)&(-6*1)+(2*3.5)\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%287%2A1%29%2B%28-2%2A3%29%26%287%2A1%29%2B%28-2%2A3.5%29%5C%5C%28-6%2A1%29%2B%282%2A3%29%26%28-6%2A1%29%2B%282%2A3.5%29%5Cend%7Barray%7D%5Cright%5D)
= ![\left[\begin{array}{ccc}(7)+(-6)&(7)+(-7)\\(-6)+(6)&(-6)+(7)\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%287%29%2B%28-6%29%26%287%29%2B%28-7%29%5C%5C%28-6%29%2B%286%29%26%28-6%29%2B%287%29%5Cend%7Barray%7D%5Cright%5D)
=
Thus, the product of the given two matrices comes out to be
Learn more about matrices here-
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A is incorrect. The identity is for the Sin( A - B). It is not for the Cos(A - B)
B is closer, but NOT the answer. The sign in the middle is incorrect, for one thing. For another Cos(pi/2) = 0,, so the answer would be cos(theta) using this formula.
C The sign is correct in C. The problem is that it is the wrong formula for Cos(theta - pi/2). C should go
Cos(theta - pi/2) = cos(theta) cos(pi/2) + sin(theta)*sin(pi/2)
D. Looks like it's the correct answer. See the comment for C: The identity for C is actually correct for D.
Cos(theta)cos(pi/2) = 0 because cos(pi/2) =0
Sin(theta)*sin(pi/2) = Sin(theta) because Sin(pi/2) = 1
Answer D <<<<<< answer.
We have been given that last month, Belinda worked 160 hours at a rate of $10.00 per hour.
Let us find amount earned by Belinda last month as:
We are also told that Belinda's employer retains 9% of her gross salary. This means that Belinda's net income will be 91% of $1600. 
.
Upon rounding $1456 to nearest hundred, we will get:
Therefore, $1500 is a reasonable estimate of her net salary.
