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3 years ago

12

Of the 36 students in the class, 8 of them are boys. If one student is picked at random, what is the probability that the studen

t will be a boy?

1 answer:

Arisa [49]3 years ago

6 0

I say if there are only 8 boys that leaves 28 girls there is a probability that it may be a boy but the chances would be low.

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In one week, Kenny works at t hours at a cafe and earns $16 per hour. He also

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Answer:

t*16+b*12=how much money per week

Step-by-step explanation:

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3 years ago

the gravitational attraction between two masses varies inversely as the square of the distance between them. if the attraction f

Marat540 [252]

Answer:

33 1/3 lb

Step-by-step explanation:

When the distance between them goes from 8 ft to 12 ft, it is 1.5 times what it was. Then the force will be multiplied by the inverse of the square of this:

(75 lb)×1/(1.5²) = 75/2.25 lb = 33 1/3 lb

At 12 feet apart, the attraction force is 33 1/3 pounds.

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4 years ago

Solve the triangle. Round your answers to the nearest tenth.

mixas84 [53]

Answer:

Angles: $\angle A = 43^{\circ}$ $\angle B = 55^{\circ}$ $\angle C = 82^{\circ}$

Sides: $BC = 20$ $AB = 29$ $AC =24$

Step-by-step explanation:

See attachment for complete question

From the attachment, we have:

$AB = 29$

$AC =24$

$\angle C = 82^{\circ}$

Required

Complete the missing side and missing angles

To calculate angle B, we apply sine laws:

$\frac{a}{sinA}=\frac{b}{sinB}=\frac{c}{sinC}$

In this case:

$\frac{AB}{sinC}=\frac{AC}{sinB}$

This gives:

$\frac{29}{sin(82^{\circ})}=\frac{24}{sinB}$

$\frac{29}{0.9903}=\frac{24}{sinB}$

Cross Multiply

$sinB * 29 = 24 * 0.9903$

Divide both sides by 29

$sinB = \frac{24 * 0.9903}{29}$

$sinB = 0.8196$

Take arcsin of both sides

$B = sin^{-1}(0.8196)$

$B = 55^{\circ}$

So:

$\angle B = 55^{\circ}$

To solve for the third angle, we make use of:

$\angle A + \angle B + \angle C = 180^{\circ}$

This gives:

$\angle A + 55^{\circ} + 82^{\circ} = 180^{\circ}$

$\angle A + 137^{\circ}= 180^{\circ}$

$\angle A = 180^{\circ}- 137^{\circ}$

$\angle A = 43^{\circ}$

Hence, the angles are:

$\angle A = 43^{\circ}$ $\angle B = 55^{\circ}$ $\angle C = 82^{\circ}$

To calculate the length of the third side, we apply cosine law

$BC^2 = AB^2 + AC^2 - 2*AB*AC*cosA$

$BC^2 = 29^2 + 24^2 - 2*29*24*cos(43^{\circ})$

$BC^2 = 841+ 576 - 1392*cos(43^{\circ})$

$BC^2 = 841+ 576 - 1392*0.7314$

$BC^2 = 841+ 576 - 1018.11$

$BC^2 = 398.89$

Take the square root of both sides

$BC = \sqrt{398.89$

$BC = 19.9722307217$

$BC = 20$

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3 years ago

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Answer:

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Step-by-step explanation:

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