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KonstantinChe [14]
3 years ago
11

5x + 3 = 7x – 1. Find x

Mathematics
1 answer:
nasty-shy [4]3 years ago
5 0

Answer:

x = 2

Step-by-step explanation:

5x + 3 = 7x - 1

Subtract 3 to both sides

5x = 7x - 4

Subtract 7x to both sides

-2x = -4

Divide by -2 to both sides.

x = 2

Hope this helps and pls do mark me brainliest if you can:)

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In this quadrilateral x=<br> A) 56. B) 67 C) 78 D) 89
Oxana [17]

the correct answer is c 78

Step-by-step explanation:

lit can't be a because to small and can't be b because also to small. and and 92 is uptus and this is an acute angle

6 0
3 years ago
What is the cosecant of angle C?
pishuonlain [190]
Cosecant = hypotenuse / opposite side    ( that is  1  / sine)
csc C =  AC / 8

AC  = sqrt (6^2 + 8^2) = sqrt 100 = 10

so cosecant of C is 10/8 = 1.25
5 0
3 years ago
Can someone help me with this right answer only and please explain it too
sineoko [7]

Answer:

g(6) = 71

f(11) = 62

Step-by-step explanation:

Let's solve g(6) first

Plug 6 into x

g(6) = 2(6)^2 - 1

g(6) = 2(36) - 1

g(6) = 72 - 1

g(6) = 71

Now let's solve f(11)

f(11) = 5(11) + 7

f(11) = 55 + 7

f(11) = 62

<em>Thus, out answers are 71 and 62 respectively</em>

5 0
3 years ago
Mathwiz wya?? pic below i need help asap
n200080 [17]

Answer:

Step-by-step explanation:

First, you gotta work out the hypotenuse of ABC, which is AC.

To do that, you need to figure out the scale factor between the two right-angled triangles. You can do that for this question because this is a similar shapes question.

12.5/5 = 2.5

The scale factor length between the two triangles is 2.5.

You can use 2.5 now to work out AC, so AC would be 13 x 2.5, which gives 32.5.

Now that you've got the hypotenuse and BC of ABC, you can use Pythagoras's theorem to work out the length of AB

Pythagoras's theorem = a^2 + b^2 = c^2

a = BC = 12.5

b = AB = we need to work this out

c = AC (the hypotenuse we just worked out) = 32.5

12.5^2 + b^2 = 32.5^2 Let's both simplify and rearrange this at the same time so that we have our b on one side.

b^{2} = 1056.25 - 156.25

b = \sqrt{(1056.25 - 156.25)}

b = \sqrt{900}

b = AB = 30  We've found b or AB, now we can work out the perimeter of ABC.

Perimeter of ABC = AB + BC + AC

= 30 + 12.5 + 32.5

= 75  Here's the perimeter for ABC.

8 0
2 years ago
Math question below down below
Elanso [62]
The letter A represents the smallest value in the data collection, which would be 17
5 0
3 years ago
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