PLEASE ANSWR ASAP!!! -Which of these landforms is created due to deposition? I

A Herbig-Haro (HH) object is:_:_________.

Phoenix [80]

Given what we know about Herbig-Haro (HH) objects, we can confirm that they are born from the collision between a jet from a star and clouds of interstellar matter.

<h3>What are Herbig-Haro (HH) objects?</h3>

To put it simply, a Herbig-Haro (HH) object is what we observe as a bright spot in distant space. Upon closer observation we can observe that these giant bright patches are not lone objects, but in fact immense groups of interstellar matter.

<h3>How Herbig-Haro (HH) objects are formed.</h3>

The formation of one of these interstellar groups requires an immense amount of energy. This energy come from the speed at which the materials that form these objects collide.
As stated in the question, the jet released from a star in the process of being born smashes into a giant cloud of dust and interstellar material to form the Herbig-Haro (HH) objects.
This collision happens at hundreds of km/s. To put it into perspective, it would be roughly 500,000 miles per hour.

Therefore, we can confirm that option b, which states, "where a jet from a star in the process of being born collides with (and lights up) a nearby cloud of interstellar matter", is the correct choice for the question pertaining to Herbig-Haro (HH) objects.

To learn more about interstellar space visit:

brainly.com/question/7106246

5 0

2 years ago

What is the freezing point of an aqueous solution that boils at 105.0 ∘C? Express your answer using two significant figures.

konstantin123 [22]

Answer:

T°fussion of solution is -18°C

Explanation:

We have to involve two colligative properties to solve this. Let's imagine that the solute is non electrolytic, so i = 1

First of all, we apply boiling point elevation

ΔT = Kb . m . i

ΔT = Boiling T° of solution - Boiling T° of pure solvent

Kb = ebuliloscopic constant

105°C - 100° = 0.512 °C kg/mol . m . 1

5°C / 0.512 °C mol/kg = m

9.7 mol/kg = m

Now that we have the molality we can apply, the Freezing point depression.

ΔT = Kf . m . i

Kf = cryoscopic constant

0° - (T°fussion of solution) = 1.86 °C/m . 9.76 m . 1

- (1.86°C /m . 9.7 m) = T°fussion of solution

- 18°C = T°fussion of solution

5 0

3 years ago

Which of the following is typical of a tropical climate?

muminat

Answer:

D

Explanation:

6 0

3 years ago

Read 2 more answers

An excess of Ba(No3)2 reacts with 250ml of H2SO4 solution to give 0.55g of BaSo4.determine The concentration in moles per litre

Wewaii [24]

Chemical reaction: Ba(NO₃)₂ + H₂SO₄ → BaSO₄ + 2HNO₃.
V(H₂SO₄) = 250 mL ÷ 1000 mL/L = 0,25 L.
m(BaSO₄) = 0,55 g.
n(BaSO₄) = m(BaSO₄) ÷ M(BaSO₄).
n(BaSO₄) = 0,55 g ÷ 233,38 g/mol.
n(BaSO₄) = 0,00235 mol.
From chemical reaction: n(BaSO₄) : n(Ba(NO₃)₂) = 1 : 1.
n(Ba(NO₃)₂) = 0,00235 mol.
c(Ba(NO₃)₂) = n(Ba(NO₃)₂) ÷ V.
c(Ba(NO₃)₂) = 0,00235 mol ÷ 0,25 L.
c(Ba(NO₃)₂) = 0,0095 mol/L.

7 0

3 years ago

Calculate the mass in 4.05*10^22 molecules of calcium phosphate

Marizza181 [45]

Answer:

m = 20.9 g.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to solve this problem by recalling both the Avogadro's number for the calculation of the moles in the given molecules of calcium phosphate and the molar mass of this compound in order to secondly calculate the mass as shown on the following setup:

$m=4.05x10^{22}molecules*\frac{1mol}{6.022x10^{23}}*\frac{310.18g}{1mol}\\\\m=20.9g$

Regards!

8 0

3 years ago