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ryzh [129]
3 years ago
13

Plz help me with this

Mathematics
1 answer:
Nana76 [90]3 years ago
3 0
This question is not even trying to test your arithmetic.  It's just testing
to see whether you know how to read numbers in words properly.

When you read numbers in words, the only time you ever say "and"
is for a decimal point.  There are no decimals in this question, so the
"and" is not a part of any numbers.

The question gives you two numbers. The word "and" is the marker
that's BETWEEN them.  The two numbers are 1,300 and 950 .

The first thing the question wants you to do is write the numerical
expression for all the words.  That's    (1300 - 950) / 4 .

The next thing you're supposed to do is"evaluate the expression" ...
find out what number it all boils down to.  I don't think you'll have
any trouble with that now.
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2ⁿ+2ⁿ+2ⁿ+2ⁿ=2¹⁶<br>value of n?​
STatiana [176]

Answer:

n = 14

Step-by-step explanation:

~~~~~~~2^n+2^n+2^n+2^n = 2^{16}\\\\\implies 4 \cdot 2^n = 2^{16}\\\\\implies 2^2 \cdot 2^n = 2^{16}\\\\\implies 2^{n+2} = 2^{16}~~~~~~~~~~~~~~~~~~~~~~~~~~~~;[a^m \cdot a^n = a^{m+n}]\\\\\implies n+ 2 = 16\\\\\implies n = 16-2 \\\\\implies n = 14

6 0
2 years ago
What solves the equation? (Needs to be simplified)
Alja [10]

\bf \cfrac{4v+1}{6v^2-19v+10}\div \boxed{x}=\cfrac{4v-1}{3v-2}\implies \cfrac{~~\frac{4v+1}{6v^2-19v+10}~~}{x}=\cfrac{4v-1}{3v-2} \\\\\\ \stackrel{\textit{cross-multipying}}{\cfrac{~~\frac{4v+1}{6v^2-19v+10}~~}{\frac{4v-1}{3v-2}}=x}\implies \cfrac{4v+1}{6v^2-19v+10}\cdot \cfrac{3v-2}{4v-1}=x \\\\\\ \cfrac{4v+1}{(\underline{3v-2})(2v-5)}\cdot \cfrac{\underline{3v-2}}{4v-1}=x\implies \cfrac{4v+1}{(2v-5)(4v-1)}=x \\\\\\ \cfrac{4v+1}{8v^2-2v-20v+5}=x\implies \cfrac{4v+1}{8v^2-22v+5}=x

8 0
3 years ago
Use the distributive property to expand the linear expression. 3(4x + 3) A) 3 4 B) 12x + 6 C) 12x + 9 D) -3 4
kipiarov [429]

Answer:

<h2>C) 12x + 9</h2>

Step-by-step explanation:

The distributive property: <em>a(b + c) = ab + ac</em>.

3(4x+3)=(3)(4x)+(3)(3)=12x+9

8 0
3 years ago
What is happening to this graph when the x-values are between - 1 and 1?
sp2606 [1]

Answer:

A. It’s decreasing

Step-by-step explanation:

<em>Hey there!</em>

<em />

Well on the graph at points -1 and 1 we can tell the line is going down,

meaning the line is decreasing.

<em>Hope this helps :)</em>

4 0
3 years ago
a circle with radious of 1cm sits inside a 11cm times 12 cm rectangle what is the area of the shaded region
Nitella [24]

Answer: 128.86cm²

Step-by-step explanation:

The circle is inscribed in the rectangle. To find the shaded portion, subtract he area of the circle from the are of the rectangle.

Area of the rectangle                                  =  11 x 12

                                                                     =  132cm²

Area of the circle with radius of 1cm          =  πr²

                                                                     = 3.142 x 1²

                                                                     = 3.142cm²

Therefore , area of the shaded  region      = 132cm²  -  3.142cm²

                                                                    = 128.86cm²

7 0
3 years ago
Read 2 more answers
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