Volume of cone=(1/3)hpir^2
d/2=r
d=2
d/2=2/2=1=r
h=6
V=(1/3)6pi1^2
V=2pi in^3 is volume
ratio of 2:1
2+1=3
2pi=3 units
divide both sides by 3
2/3pi=1 unit
vanila=2 units
times 2/3pi by 2
4/3pi
aprox pi=3.141592
4.188
round
4.2 in^3 of vanilla
2a+b4.....................
Answer:
D
Step-by-step explanation:
For the largest area, half the fence is used parallel to the river, and the other half is used for the two ends of the rectangular space.
The dimensions are 475 m by 237.5 m.
_____
Let x represent the length along the river. Then the area (A) is found as
.. A = x*(950 -x)/2
This equation describes a parabola with its vertex (maximum) halfway between the zeros of x=0 and x=950. That is, the maximum area is achieved when half the fence is used parallel to the river.
Well first find the area of the semi-circle.
If the area of a cricle is equal to pi*radius^2 , then you can just find that and divide by 2.
So, A = pi*2^2. = 4pi
We know that the radius is 2 because the length of the side of the rectangle is 4, meaning that the diameter of the semi-circle is 4, and so the radius is 2 as it is half of the diameter.
We can easily calculate the area of the rectangle, which is
Length * width = 6*4 = 24.
Next we divide 4pi by 2 in order to get the area of the semi-circle, giving us an area of 2pi
We can just subtract 2pi from 24 and get the area of the shaded region.
Area of the shaded region (answer): 17.7