Answer:
Cameron found 23 quarters and 57 dimes.
Step-by-step explanation:
Let the number of quarters Cameron found = Q
And the number of dimes = D
Since, total number of coins were 80,
Q + D = 80 -----(1)
Total amount of the coins was $11.45,
0.1D + 0.25Q = 11.45
10D + 25Q = 1145
2D + 5Q = 229 -----(2)
Equation (1) multiplied by 2 then subtracted by equation (2),
(2D + 5Q) - 2(Q + D) = 229 - 2(80)
(2D - 2D) + (5Q - 2Q) = 229 - 160
3Q = 69
Q = 23
From equation (1),
23 + D = 80
D = 57
Cameron found 23 quarters and 57 dimes.
