Answer:
I think the answer is 2. Hope this helps!
The 15th term will be 71. Why? Well, see below for an explanation!
By subtracting all of these numbers by the term that comes prior to them, we will find that all of them result in 5. Because of this, we know that each time the term increases, 5 is being added to the numbers. Additionally, I noticed that all of the numbers in this arithmetic sequence only end in a 1 or a 6. Because of this, we can apply the same principle when adding 5 each time:
First term: 1
Second term: 6
Third term: 11
Fourth term: 16
Fifth term: 21
Sixth term: 26
Seventh term: 31
Eighth term: 36
Ninth term: 41
Tenth term: 46
Eleventh term: 51
Twelfth term: 56
Thirteenth term: 61
Fourteenth term: 66
Fifteenth term: 71
By adding 5 each time and keeping in mind that the digits all end in only 1 or 6, we will find that the fifteenth term results in 71. Therefore, the 15th term is 71.
Your final answer: The 15th term of this arithmetic sequence comes down to be 71. If you need extra help, let me know and I will gladly assist you.
Answer: 0
Step-by-step explanation:
h ( t ) = − 2 t ^2 + 10 t
h = height of ball above the ground
t = time, seconds after ball was kicked
Height of ball at the time it is kicked?
At the time ball is kicked, time (t) = 0
Therefore,
h ( t ) = − 2 t ^2 + 10 t
h( 0) = - 2(0)^2 + 10(0)
h = 0 + 0
h = 0
The ball was the on the grounf at the time it was kicked.
Well the 2 in the tens place is ten times as many as the 2 in the hundreds place.Also the 5 in the thousand place is 10 times as many as the 5 in the ten thousand place
Answer:
2
Step-by-step explanation:
6x3 = 18
4x3 = 12
18 - 12 = 6
16 / 4 = 4
6 - 4 = 2
