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frosja888 [35]
3 years ago
9

David drove 36 mph and reached camp in 1.5 hours. How long will it take him to drive home if he takes the same route and drives

45 mph?
Mathematics
2 answers:
kobusy [5.1K]3 years ago
7 0

Answer:

1.2 hours

Step-by-step explanation:

to find distance for 36 mph

0.5 hour is 18 miles

so 36m+18m

= 54 miles for 1.5 hours

and to find time for 45 mph

54 \div 45 =    \frac{6}{5}  \\  = 1.2

Arturiano [62]3 years ago
5 0

Answer:

1.2 hours, or 72 minutes

Step-by-step explanation:

If David drove for 1.5 hours at 36 mph, that means that he traveled a distance of (36*1.5) = 54 miles.

If he takes the same route at a speed of 45 mph instead, he will reach his destination in (54/45) = 1.2 hours, which is equivalent to 72 minutes.

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Galina-37 [17]

Answer:

12 i believe

Step-by-step explanation:

volume; LxWxH

3x2x2

3x2=6

6x2=12

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6 0
3 years ago
What is the value of x?
artcher [175]
By Sine Rule,

x/sin30° = 8/sin90°

x/0.5 = 8/1

So x = 4.
8 0
3 years ago
Read 2 more answers
Please solve for the hypotenuse of a right triangle having legs 6 and 8. *
Arturiano [62]

Answer:

10

Step-by-step explanation:

6²+8²

=100

√100

=10

6 0
3 years ago
The average salary of all residents of a city is thought to be about $39,000. A research team surveys a random sample of 200 res
Rina8888 [55]

Answer:

z=\frac{40000-39000}{\frac{12000}{\sqrt{200}}}=1.179    

p_v =2*P(z>1.179)=2*[1-P(Z    

Step-by-step explanation:

Data given and notation    

\bar X=4000 represent the average score for the sample    

s=12000 represent the sample standard deviation    

n=200 sample size    

\mu_o =39000 represent the value that we want to test    

\alpha represent the significance level for the hypothesis test.    

z would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)    

State the null and alternative hypotheses.    

We need to apply a two tailed test.    

What are H0 and Ha for this study?    

Null hypothesis:  \mu = 39000    

Alternative hypothesis :\mu \neq 39000    

Compute the test statistic  

The sample size is large enough to assume the distribution for the statisitc normal. The statistic for this case is given by:    

z=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)    

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

We can replace in formula (1) the info given like this:    

z=\frac{40000-39000}{\frac{12000}{\sqrt{200}}}=1.179    

Give the appropriate conclusion for the test  

Since is a two tailed test the p value would be:    

p_v =2*P(z>1.179)=2*[1-P(Z    

Conclusion    

If we compare the p value and a significance level given for example \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, then the true population mean for the salary not differs significantly from the value of 39000.    

6 0
3 years ago
Help me pleaseee asap !!!
frosja888 [35]

Step-by-step explanation:

5x+3x-14=180

8x-14=180

8x=180+14

8x=174

x=174/8

x= 21.75°

if x is 21.75°, then 5x is 108.75°

which means 3x-14 is 51.25°

therefore, f +108.75+51.25=180

f = 180-160

f=20°

4 0
3 years ago
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