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natali 33 [55]
3 years ago
15

Calculate acceleration of an object moving from a stop to 21 m/s in 3.9 s

Physics
2 answers:
Alex3 years ago
7 0
5.38
21 divided by 3.9 is 5.38 and the equation for acceleration is change in velocity divided by time
tresset_1 [31]3 years ago
6 0

Heya!!

For calculate aceleration, lets applicate formula:

                                                   \boxed{a=\frac{V-V_o}{t} }

                                                   <u>Δ   Being   Δ</u>

                                          V = Final Velocity = 21 m/s

                                         Vo = Initial Velocity = 0 m/s

                                          a = Aceleration =  ? m/s²

                                                  t = Time = 3,9 s

⇒ Let's replace according the formula:

\boxed{a=\frac{21\ m/s - 0 \ m/s}{3,9\ s} }

⇒ Resolving

\boxed{ a=5,38\ m/s^{2}}

Result:

The aceleration of the object is <u>5,38 m/s²</u>

Good Luck!!

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