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alex41 [277]
2 years ago
15

PLEASE HELP ITS DUE TODAY ILL POST THE OTHER HALF

Physics
2 answers:
KIM [24]2 years ago
7 0
B c d a c a c a c c c
IgorLugansk [536]2 years ago
4 0
2.B
4.C
3.D
1.C
5.C
Theses are the right answer
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The answer should be B: 500g of mass on bottom.
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Does the mass of a parachute affect terminal velocity?
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The greater weight increases the terminal velocity by acting as an extra force against gravity and air resistance.

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Calculate the percentage increase in speed of the cyclist when the power output changes from 200 W to 300 W.
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<em>50%</em>

Explanation:

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Final power = 300W

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he tune-up specifications of a car call for the spark plugs to be tightened to a torque of 47 N⋅m . You plan to tighten the plug
S_A_V [24]

Answer:

207.4 N

Explanation:

The torque \tau  on a body is

\tau = r* F  where r is the radius vector from the point of rotation to the point at which force F is applied.

The product of r and F is equal to the product of magnitude of r and F multiplied by the sine of angle between both vectors.

Therefore, torque is also given by

\tau = rF\sin \theta

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Use the expression of torque.

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\tau = LF\sin \theta

Where L is the length of the wrench.

Making F the subject

F = \frac{\tau }{{L\sin \theta }}

Force required to pull the wrench is given as,

F = \frac{\tau }{{L\sin \theta }}

Substitute 47{\rm{ N}} \cdot {\rm{m}}  for \tau, 25 cm for L, and 115o for \theta  

\begin{array}{c}\\F = \frac{{47{\rm{ N}} \cdot {\rm{m}}}}{{\left( {25{\rm{ cm}}} \right)\sin {{115}^{\rm{o}}}}}\left( {\frac{{1{\rm{ cm}}}}{{{{10}^{ - 2}}{\rm{ m}}}}} \right)\\\\ = 207.435{\rm{ N}}\\\\ \approx 207.4{\rm{ N}}\\\end{array}  

6 0
3 years ago
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