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lions [1.4K]
3 years ago
7

Damarcus and Xavier went to the arcade to play their two favorite games. Damarcus played 4 rounds of game 1 and 6 rounds of game

2 for $18.00. Xavier played 5 rounds of each game for $20. What is is the cost of game 1?
Mathematics
2 answers:
nlexa [21]3 years ago
8 0

Answer:

I think the cost of game 1 is $8

Step-by-step explanation:

dezoksy [38]3 years ago
4 0
The cost of one game is 8
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G is between F and H, FG = 8, and FH = 12.<br> Find GH.<br> O GH= 4<br> O GH = 12<br> O GH = 5
ANEK [815]

Answer:

GH = 4

Step-by-step explanation:

Since G is between F and H then

FG + GH = FH , that is

8 + GH = 12 ( subtract 8 from both sides )

GH = 4

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Step-by-step explanation:

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4 years ago
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aleksley [76]

Answer:

a)2\sqrt{2}=\sqrt{8}

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c)\frac{1}{3} \sqrt{18b}  =\sqrt{2.b}

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Step-by-step explanation:

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b)-7\sqrt{3} =-(\sqrt{7} )^2\sqrt{3} =-\sqrt{7^2.3} =-\sqrt{147}

c)\frac{1}{3} \sqrt{18b} =\frac{1}{3} \sqrt{9.2.b} =\frac{1}{3} \sqrt{3^2.2.b} =\frac{1}{3} \times 3\sqrt{2.b} =\sqrt{2.b}

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3 years ago
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