Question

Hello, can anyone help me with this question?

Answer 1

Answer: a.  $11.9\times 10^{23}atoms$ of carbon

b. $35.7\times 10^{23}atoms$ of hydrogen

c. $5.96\times 10^{23}atoms$ of oxygen

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar Mass}}=\frac{45.6g}{46.07g/mol}=0.989moles$

a) 1 mole of ethanol $(C_2H_5OH)$ contains = $2\times 6.023\times 10^{23}=12.05\times 10^{23}atoms$ of carbon

Thus 0.989 moles ethanol $(C_2H_5OH)$ contains = $\frac{12.05\times 10^{23}}{1}\times 0.989=11.9\times 10^{23}atoms$ of carbon

b) 1 mole of ethanol $(C_2H_5OH)$ contains = $6\times 6.023\times 10^{23}=36.14\times 10^{23}atoms$ of hydrogen

Thus 0.989 moles ethanol $(C_2H_5OH)$ contains = $\frac{36.14\times 10^{23}}{1}\times 0.989=35.7\times 10^{23}atoms$ of hydrogen

c)  1 mole of ethanol $(C_2H_5OH)$ contains = $6.023\times 10^{23}atoms$ of oxygen

Thus 0.989 moles ethanol $(C_2H_5OH)$ contains = $\frac{6.023\times 10^{23}}{1}\times 0.989=5.96\times 10^{23}atoms$ of oxygen