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kenny6666 [7]
3 years ago
15

Help please chemistry question

Chemistry
1 answer:
Gemiola [76]3 years ago
3 0

Answer:

D. K_{a} = \frac{[\text{H}^{+}][\text{NO}_{2}^{-}]}{[\text{HNO}_{2}]}

Explanation:

The general form of an equilibrium constant expression is

K = \frac{[\text{Products}]}{[\text{Reactants}]}

In the equilibrium

HNO₂ ⇌ H⁺ + NO₂⁻

The products are H⁺ and NO₂⁻, and the reactant is HNO₂.

∴ K_{a} = \frac{[\text{H}^{+}][\text{NO}_{2}^{-}]}{[\text{HNO}_{2}]}

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