Question:
1. The females worked less than the males, and the female median is close to Q1.
2. There is a high data value that causes the data set to be asymmetrical for the males.
3. There are significant outliers at the high ends of both the males and the females.
4. Both graphs have the required quartiles.
Answer:
The correct option is;
1. The females worked less than the males, and the female median is close to Q1
Step-by-step explanation:
Based on the given data, we have;
For males
Minimum = 0
Q1 = 1
Median or Q2 = 20
Q3 = 25
Maximum = 50
For females;
Minimum = 0
Q1 = 5
Median or Q2 = 6
Q3 = 10
Maximum = 18
Therefore, the values of data that affect the statistical measures of spread and center are that
The females worked less than the males as such the statistical data for the females have less variability than the males in terms of interquartile range
Also the female median is very close to Q1, therefore it affects the definition of a measure of center.
You have the right answer but for the second part it's 65+10/5=x
Answer:
105 minutes.
Step-by-step explanation:
first you would subtract 60 by 20 to get 40 then your time would be at 9:00 so in order to get to 10:00 you would have 60 minutes which you would add the 40 to to get 100 minutes then add 5 to bring your time to 10:05 and your total number of minutes to 105
1/4 is the same thing as 25%. So we know that we have to find 25% of 2000 pounds, which is 1 ton. Convert 25% into a decimal and then multiply.
2000 times .25 is 500.
One fourth of one ton is 500 pounds.
Answer:
Yes, The analysis involves a statistical test.
The hypothesis are 
Step-by-step explanation:
Consider the provided information.
Testing 500 right-handed participants on the reaction time of their left and right hands to determine if there is evidence for the claim that the right hand reacts faster than the left.
Yes, The above analysis involves a statistical test.
Where claim is right hand reacts faster than the left hand.
If right hand reacts faster that means the reaction time of right hand should be smaller than the reaction time of left hand.
Let 
to be the average reaction time of their right hands for the right-handed participants and 
to be the average reaction time of their left hands.
Therefore, the hypothesis are
