X^2 + y^2 = z^2
d/dt[ x^2 + y^2 ] = d/dt[ z^2 ]
d/dt[ x^2 ] + d/dt[ y^2 ] = d/dt[ z^2 ]
2x*dx/dt + 2y*dy/dt = 2z*dz/dt
x*dx/dt + y*dy/dt = z*dz/dt
12*(3*dy/dt) + 5*dy/dt = z*1
12*(3*dy/dt) + 5*dy/dt = 13
12*(3*w) + 5*w = 13 ... letting w = dy/dt
36*w + 5*w = 13
41*w = 13
w = 13/41
dy/dt = 13/41
dx/dt = 3*(dy/dt)
dx/dt = 3*(13/41)
dx/dt = 39/41
You have the correct answer. Nice job.
( 4 )is this 1st grade or something?
Answer:
2
Step-by-step explanation:
2 x 0= 0 + 2 = 2
Answer:
Hence, 0.00000103 can be expressed as
.
Step-by-step explanation:
- Given 0.00000103
- Move the decimal point so that the factor is greater than or equal to 1 but less than 10 .
- Then count n and write no. as a product with a power of 10 .
Step 1 of 1
Consider 0.00000103,
1.03
Decimal has moved 6 places to right.
The power will be negative as the original no. is less than 1 .

So k=1000 like 4k=4 000 so 6/7 of a thousnad =0.857142857 so times 6=0.857142857