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stepan [7]
3 years ago
10

Elena's backyard is in the shape of a rectangle. She created a triangular-shaped flower bed (shown as the shaded region) to plan

t flowers in.
20 feet
10 feet
25 foot
35 feet
The area of the triangular flower bed is
square
square feet. The area of her backyard that does not include the flower bed is
feet

Mathematics
1 answer:
Scorpion4ik [409]3 years ago
8 0
25 feet I don’t know hard problem sorry 24hhk
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Which of the following is a solution of x2 + 5x = −2? (2 points) 5 plus or minus the square root of 33 divided by two. 5 plus or
Delicious77 [7]
The easiest way it to solve it.
{x}^{2}  + 5x + 2 = 0
You have
\rho = 25 - 4 \times 1 \times 2 = 17
Thus
x =  \frac{ - 5 \pm \sqrt{17} }{2}
5 0
3 years ago
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PLEASE HELP ME WITH THIS PROBLEM IVE BEEN ON IT FOR 3 DAYS NOW!
Len [333]
85 x 3 = 255
 first 2 test grades were 81 and 86:
81 + 86 = 167

Need to find the 3rd to have exact average 85:
255 - 167 = 88

So her 3rd test needs to make 88 to make average of 85

Double check: 81 + 86 + 88 =  255 = 85 + 85 + 85
3 0
3 years ago
Question in the picture!
Sunny_sXe [5.5K]

Answer:

  x = 12

Step-by-step explanation:

Vertical angles are congruent, so ...

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8 0
3 years ago
A sample of 11 students using a Ti-89 calculator averaged 31.5 items identified, with a standard deviation of 8.35. A sample of
lina2011 [118]

Answer:

We reject H₀, with CI = 90 % we can conclude that the mean numbers of times identified with Ti-84 does not exceed that of the Ti-89 by more than 1,80

Step-by-step explanation:

Ti-89 Calculator

Sample mean     x = 31,5

Sample standard deviation   s₂  = 8,35

Sample size        n₂ = 11

Ti-84 Calculator

Sample mean     y = 46,2

Sample standard deviation   s₁  = 9,99

Sample size        n₁ = 12

t(s)  = ( y - x - d ) / √s₁²/n₁ + s₂²/n₂

t(s)  = 12,9 / √(99,8/12) + (69,72/11)

t(s)  = 12,9 / √8,32 + 6,34

t(s)  = 12,9 / 3,83

t(s) = 3,37

Test Hypothesis

Null Hypothesis               H₀      y - x > 1,80

Altenative Hypothesis       Hₐ      y - x ≤ 1,80

We have a t(s) = 3,37

We need to compare with t(c)   critical value for

t(c) α; n₁ +n₂-2            df = 12 +11 -2     df  = 21

If we choose  CI = 95 %    then  α = 5 %   α = 0,05

From t-student table

t(c) = 1,72

t(s) = 3,37

t(s) >t(c)

t(s) is in the rejection region therefore we accept Hₐ with CI = 95 %

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3 years ago
Help me with math pls ❤️ it will mean a lot to me.
Keith_Richards [23]
7/6

Hope this helps!!!!
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