Answer:
2^5 and 3^4
Step-by-step explanation:
you can see there are 5 2's and 4 3's. so it would be 2^5 and 3^4
Answer:
x=2 or x=3
Step-by-step explanation:
x^4 - 5x^3 + 7x^2 - 5x + 6 = 0
Step 1=Factor left side of equation.
(x-2) (x-3) (x^2 + 1) = 0
Step 2=Set factors equal to 0.
x-2 = 0 or x-3 = 0 or x^2 + 1 = 0.
Answer:x=2 or x=3
Answer:
a)120
b)6.67%
Step-by-step explanation:
Given:
No. of digits given= 6
Digits given= 1,2,3,5,8,9
Number to be formed should be 3-digits, as we have to choose 3 digits from given 6-digits so the no. of combinations will be
6P3= 6!/3!
= 6*5*4*3*2*1/3*2*1
=6*5*4
=120
Now finding the probability that both the first digit and the last digit of the three-digit number are even numbers:
As the first and last digits can only be even
then the form of number can be
a)2n8 or
b)8n2
where n can be 1,3,5 or 9
4*2=8
so there can be 8 three-digit numbers with both the first digit and the last digit even numbers
And probability = 8/120
= 0.0667
=6.67%
The probability that both the first digit and the last digit of the three-digit number are even numbers is 6.67% !
50 + (100% of 50) =
50 + 1(50) =
50 + 50 =
100 <===
That's not true because the GCF of 9 and 12 are both three and three is an odd number
