Answer:
Interquartile range = 24
Step-by-step explanation:
First we need to put the sequence in order from lowest to highest.
0, 1, 3, 5, 21, 25, 45
5 is the median and then from 5 to 0 we need to find the lowest interquartile in between it which is 1.
Highest interquartile from 5 to 45 finding the middle will be 25.
Interquartile range = highest interquartile - lowest quartile
25-1 = 24
1 yd = 3 ft
39 ft/m = 13 yd/m
1 min = 60 sec
13 yd/60 sec = .21667 yd/sec
A heptagon has 7 sides, so 7-2=5
Answer:
Step-by-step explanation:
Given the following lengths AB = 64, AM = 4x + 4 and BM= 6x-10, If M lies on the line AB then AM+MB = AB (addition property)
Substituting the given parameters into the addition property above;
AM+MB = AB
4x + 4 + 6x - 10 = 64
combine like terms
4x+6x = 64+10-4
10x = 74-4
10x = 70
Divide both sides by 10
x = 70/10
x = 7
Note that for M to be the midpoint of AB then AM must be equal to BM i.e AM = BM
To get AM ;
Since AM = 4x+4
substitute x = 7 into the function
AM = 4(7)+4
AM = 28+4
AM = 32
Similarly, BM = 6x-10
BM = 6(7)-10
BM = 42-10
BM = 32
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<em>Since AM = BM = 32,. then M is the midpoint of AB</em>
Answer:
2 or wrong answer 55
Step-by-step explanation:
