2.5 years required for an investment of 5000 dollars to grow to 6000 dollars at an interest rate of 7.5 percent per year, compounded quarterly.
Step-by-step explanation:
The given is,
Initial investment - $5000
Future amount - $6000
Interest rate - 7.5% (compounded quarterly)
Step:1
Formula to calculate the Future amount with compound interest,
...................................(1)
Where, F - Future amount
P - Initial amount
r - Rate of interest
n - No. of compounding in a year
t - Time period
From given,
F = $6000
P = $5000
r = 7.5%
n = 4 (compounded quarterly)
Equation (1) becomes,



Take log on both sides,

Substitute log values,
0.07918 = 4(t) (0.0080676)
= (t) (0.0322705)
= 2.45
t ≅ 2.5 years
Result:
2.5 years required for an investment of 5000 dollars to grow to 6000 dollars at an interest rate of 7.5 percent per year, compounded quarterly.
Answer:
50th term is -338
Step-by-step explanation:
Common difference d = -2-5 = -7
first term is a1 = 5
50th term
a50 = a1 + (n -1)d
a50 = 5 -7(50-1)
a50 = 5 -7(49)
a50 = -338
Hope this will helpful.
Thank you.
By solving given equations, the value of c is 30.
Given two equations
x + 2y = 10 and
3x + 6y = c
These lines represents the same line for some constant c.
Value of c:
x + 2y = 10-------------(1)
3x + 6y = c-------------(2)
Dividing equation (2) by 3

After solving the above equation, we get
x + 2y = c/3-----------(3)
Remember that a line is written as ax + by = c, in our case, both lines have a =1 and b = 2. Therefore, in orther that the two lines are equal, we need that, 10 = c/3
c = 10 × 3 = 30
c = 30
Therefore,
The value of c is 30.
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3x - 6y = -2
-6y = -3x - 2, divide through by -1
6y = 3x + 2, divide through by 6
y = 3x/6 + 2/6
y = x/2 + 1/3