1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vovangra [49]
4 years ago
12

Plot the image of point Q under a reflection across the -axis.

Mathematics
1 answer:
Jlenok [28]4 years ago
7 0

Answer:

pit it on -4 because your reflecting it on x

You might be interested in
WILL GIVE 30 points a scatter plot and a possible line of best fit is shown is the line of best fit accurate for the data shown
Romashka [77]
I think It is 2. it makes the most sense to me
5 0
3 years ago
Simplify 32^-1/5 Thanks in advance!!!
jeka94

Fractional index means "xth root of". Negative index means a fraction. So together, what it really means is:

\frac{1}{\sqrt[5]{32}} = \frac{1}{2}.

3 0
3 years ago
According to a Yale program on climate change communication survey, 71% of Americans think global warming is happening.† (a) For
SpyIntel [72]

Answer:

a) 0.2741 = 27.41% probability that at least 13 believe global warming is occurring

b) 0.7611 = 76.11% probability that at least 110 believe global warming is occurring

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

p = 0.71

(a) For a sample of 16 Americans, what is the probability that at least 13 believe global warming is occurring?

Here n = 16, we want P(X \geq 13). So

P(X \geq 13) = P(X = 13) + P(X = 14) + P(X = 15) + P(X = 16)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 13) = C_{16,13}.(0.71)^{13}.(0.29)^{3} = 0.1591

P(X = 14) = C_{16,14}.(0.71)^{14}.(0.29)^{2} = 0.0835

P(X = 15) = C_{16,15}.(0.71)^{15}.(0.29)^{1} = 0.0273

P(X = 16) = C_{16,16}.(0.71)^{16}.(0.29)^{0} = 0.0042

P(X \geq 13) = P(X = 13) + P(X = 14) + P(X = 15) + P(X = 16) = 0.1591 + 0.0835 + 0.0273 + 0.0042 = 0.2741

0.2741 = 27.41% probability that at least 13 believe global warming is occurring

(b) For a sample of 160 Americans, what is the probability that at least 110 believe global warming is occurring?

Now n = 160. So

\mu = E(X) = np = 160*0.71 = 113.6

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{160*0.71*0.29} = 5.74

Using continuity correction, this is P(X \geq 110 - 0.5) = P(X \geq 109.5), which is 1 subtracted by the pvalue of Z when X = 109.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{109.5 - 113.6}{5.74}

Z = -0.71

Z = -0.71 has a pvalue of 0.2389

1 - 0.2389 = 0.7611

0.7611 = 76.11% probability that at least 110 believe global warming is occurring

3 0
3 years ago
Will mark brainliest if you help!!!!!​
Katyanochek1 [597]

Answer:

.70

Step-by-step explanation:

5 and up round up so it would round to .7

3 0
3 years ago
Gabriel wants to paint the model. How
enyata [817]

Answer:

<h2>The area of the base is 144 square inches.</h2><h2>The area of each triangular face is 66 square inches.</h2><h2>Grabiel needs 408 square inches of paint.</h2>

Step-by-step explanation:

The complete problem is attached.

Notice that the figure is a square pyramid, where its base dimensions are 12 inches by 12 inches, which represents an area of

B=12 \times 12 = 144 \ in^{2}

The slant height of the pyramid is 11 inches, which allow us to find the area of each triangle face

A=\frac{1}{2}bh =\frac{1}{2}(12)(11)= 66 \ in^{2}

But there are four triangle faces, so A_{faces} =4(66)=264 \ in^{2}.

Therefore, the area of each triangular face is 66 square inches.

So, the total surface area would be the sum

S=144+264=408 \ in^{2}

Therefore, Gabriel needs 408 square inches to paint the whole model.

4 0
3 years ago
Other questions:
  • Is the following sequence arithmetic? If so, identify the common difference. 2.9, 2.7, 2.5, 2.3,
    13·2 answers
  • The different of anumber and 12
    8·1 answer
  • PLEASE HELP!! I’ll mark brainliest!! Image of the figure will be attached. 2.5 2.5 and 5 are the numbers! To get brainliest plea
    5·2 answers
  • Karla has spent $42 on food. She bought
    11·1 answer
  • Write the ratio of height of the building to the number of floors.​ Then, find the unit​ rate, and explain what it means in this
    5·1 answer
  • Trigonometry can anyone help me out
    14·2 answers
  • Sin data <br>cos data <br>tan data<br>csc date <br>sec data <br>cot data ​
    7·1 answer
  • Draw a line through point B that is perpendicular to AC. Label the intersection of the line and AC as point D. Take a screenshot
    7·2 answers
  • There are 20 pieces of fruit in a fruit bowi and 12 of them are apples. What percentage of the pieces of fruit in the bowl are a
    8·1 answer
  • PLEASE SHOW WORK ILL GIVE BRAINLIEST DUE TODAY!!!
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!