Using an exponential equation, it is found that it will be 7.3 years before the value is doubled.
The equation for an increasing <u>exponential function</u> is given by:

In which:
- A(0) is the initial amount.
- r is the growth rate, as a decimal.
In this problem:
- Gains 10% each year, thus
.
The doubling time is t for which
, then:







It will be 7.3 years before the value is doubled.
A similar problem is given at brainly.com/question/23008760
8 + 36 / 11 - 7
44/4
11
so your answer will be
B. 11
Answer:
4 hundreds and point 4 thousandths
Step-by-step explanation:
You have to write a number using place value units.
Answer:
$330
Step-by-step explanation:
It seems it should be the other way... . How soon will the puppy catch up with the kitten.
The way you have it the kitten will never catch the pup. There is already 180m between them so, the distance will only increase because the puppy runs faster than the cat.
If the puppy runs after the cat, will eventually catch up with it and can be calculated. Not the other way around.
If the pup runs after the cat, the distance between them will decrease and the pup will catch the cat.
RT = D kitten
RT = D+180 puppy
20T = D
25T = D + 180
Substitution
25T = 20T +180
5T = 180
T = 36s