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Dmitry_Shevchenko [17]
3 years ago
7

Whats the equation of the line?

Mathematics
1 answer:
Phantasy [73]3 years ago
3 0

Answer: I believe it should be answer B

Step-by-step explanation: the x coordinate pairs with y and vice versa and if it’s positive you subtract is how I remember it.

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I need help on my homework pls
son4ous [18]

Answer:

y=x2

I got it solved! tell me if it helped

4 0
2 years ago
Read 2 more answers
What are zeroes of f(x) =x^2-x-2
allochka39001 [22]
You have to factor this...
 So you have started with this...

x²-x-2=0
If you factor this you will get

(x+1)(x-2)=0

This gives you two solutions...
x=-1, x=2
Hope this helps! Give me a five-rate and a thanks!
6 0
3 years ago
assume that the number of production defects is 28 and that 14 of these are classified as major defects, 8 are classified as des
Arlecino [84]

Answer:  5

Step-by-step explanation:

Let A denotes the number of major defects and B denotes the number of design defect.

By considering the given information, we have

U=28\ ;\ n(A)=14\ ;\ n(B)=8\ \ ;\ n(A^c\cap B^c)=1

Now, the number of major defects or design defects:

n(A\cup B)=U-n(A^c\cap B^c)=28-11=17

Also,

n(A\cap B)=n(A)+n(B)-n(A\cup B)\\\\\Rightarrow\ n(A\cap B)=14+8-17=5

Hence, the number of  design defects were major=5

6 0
3 years ago
A spherical balloon was inflated such that it had a diameter of 24 centimeters. Additional helium was then added to the balloon
DanielleElmas [232]
To solve this we are going to use the formula for the volume of a sphere: V= \frac{4}{3}  \pi r^3
where 
r is the radius of the sphere 

Remember that the radius of a sphere is half its diameter; since the first radius of our sphere is 24 cm, r= \frac{24}{2} =12. Lets replace that in our formula: 
V= \frac{4}{3} \pi r^3
V= \frac{4}{3} \pi (12)^3
V=7238.23 cm^3

Now, the second diameter of our sphere is 36, so its radius will be: r= \frac{36}{2} =18. Lets replace that value in our formula one more time:
V= \frac{4}{3} \pi r^3
V= \frac{4}{3} \pi (18)^3
V=24429.02

To find the volume of the additional helium, we are going to subtract the volumes:
Volume of helium=24429.02cm^3-7238.23cm^3=17190.79cm^3

We can conclude that the volume of additional helium in the balloon is approximately <span>17,194 cm³.</span>
8 0
3 years ago
24 and 25 thanksssssss
german
24:D
25:C
you’re welcome
6 0
2 years ago
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