Answer:
B
Step-by-step explanation:
Given the 2 equations
x³ + y = 0 → (1)
11x² - y = 0 → (2)
Add (1) and (2) term by term to eliminate the term in y
x³ + 11x² = 0 ← factor out x² from each term
x²(x + 11) = 0
Equate each factor to zero and solve for x
x² = 0 ⇒ x = 0
x + 11 = 0 ⇒ x = - 11
Substitute these values into (1) for corresponding values of y
(1) y = - x³
x = 0 ⇒ y = 0 ⇒ (0, 0) is a solution
x = - 11 ⇒ y = - (- 11)³ = 1331 ⇒ (- 11, 1331) is a solution
Alright, this is an easy one!
So we are trying to get rid of the y value so the first equation has -3y. The second equation has 2y. What values would make these equal.
A.) 2*-3y = -6y and 3 * 2y = 6y.
Now take -6y + 6y and that gives you 0.
Thus, the answer is A.) <span>Multiply the first equation by 2 and the second equation by 3. </span>
X = 9
Move the 1 over to make it 3x = 28. The. 28/3 equals 9
