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VikaD [51]
2 years ago
6

Need the answer to this

Mathematics
1 answer:
ki77a [65]2 years ago
4 0

Answer:

\frac{2}{(x + 3)}

Step-by-step explanation:

\frac{2x - 10}{x^{2} - 2x - 15}

pull 2 from top

\frac{2(x - 5)}{x^{2} - 2x - 15}

we are looking to cancel (x-5) so will start with

(x - 5)(x + 3), selected (x+3) because the sign must be negative and must multiply to -15

\frac{2(x - 5)}{(x - 5)(x + 3)}  

now cancel (x-5)

\frac{2}{(x + 3)}

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Show work <br><br><br><br>4x + 3 =6x+9 ​
Paraphin [41]

Answer:

x = -3

Step-by-step explanation:

4x+3 = 6x+9

4x-6x = 9-3

-2x = 6

x = -3

8 0
3 years ago
What is the minimum force required to prevent a ball weighing 22.6 lb from rolling down a ramp which is inclined at 39.0 degrees
Alona [7]
The correct answer is 14.2 lb which is choice D.

Let:

F = minimum force required to prevent ball from rolling down the ramp

The formula will be:

F = w * sin theta

F = w * sin (39 degrees)

F = 22.6 * sin (39) 
= 14.2 lb (this is rounded to the nearest tenth)
7 0
3 years ago
What is the absolute value of a number
Minchanka [31]
The answer your looking for is 5
8 0
3 years ago
Read 2 more answers
What is the result of substituting for y in the bottom equation<br> y=x+3<br> y=x^2+2x-4
8_murik_8 [283]

The solutions are (2.1925, 5.1925) and (-3.1925, -0.1925)

<em><u>Solution:</u></em>

Given that,

y = x + 3 ------- eqn 1\\\\y = x^2 + 2x - 4  ----- eqn 2

<em><u>We have to substitute eqn 1 in eqn 2</u></em>

x + 3 = x^2 + 2x - 4

\mathrm{Switch\:sides}\\\\x^2+2x-4=x+3\\\\\mathrm{Subtract\:}3\mathrm{\:from\:both\:sides}\\\\x^2+2x-4-3=x+3-3\\\\\mathrm{Simplify}\\\\x^2+2x-7=x\\\\\mathrm{Subtract\:}x\mathrm{\:from\:both\:sides}\\\\x^2+2x-7-x=x-x\\\\\mathrm{Simplify}\\\\x^2+x-7=0

\mathrm{Solve\:with\:the\:quadratic\:formula}\\\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=1,\:b=1,\:c=-7\\\\x =\frac{-1\pm \sqrt{1^2-4\cdot \:1\left(-7\right)}}{2\cdot \:1}

x = \frac{-1 \pm \sqrt{ 1 + 28}}{2}\\\\x = \frac{ -1 \pm \sqrt{29}}{2}

x = \frac{ -1 \pm 5.385 }{2}\\\\We\ have\ two\ solutions\\\\x = \frac{ -1 + 5.385 }{2}\\\\x = 2.1925

Also\\\\x = \frac{ -1 - 5.385 }{2}\\\\x = -3.1925

Substitute x = 2.1925 in eqn 1

y = 2.1925 + 3

y = 5.1925

Substitute x = -3.1925 in eqn 1

y = -3.1925 + 3

y = -0.1925

Thus the solutions are (2.1925, 5.1925) and (-3.1925, -0.1925)

6 0
3 years ago
Is (-3, 1) a solution to this system of inequalities?
Maksim231197 [3]

Answer:

No

Step-by-step explanation:

5(-3)= -15

5(1)= 5

-15+5=-10

-10 is greater than -19 not less than or equal too.

Hope this helps!

5 0
2 years ago
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