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2 years ago

Need the answer to this

Mathematics

1 answer:

ki77a [65]2 years ago

4 0

Answer:

$\frac{2}{(x + 3)}$

Step-by-step explanation:

$\frac{2x - 10}{x^{2} - 2x - 15}$

pull 2 from top

$\frac{2(x - 5)}{x^{2} - 2x - 15}$

we are looking to cancel (x-5) so will start with

(x - 5)(x + 3), selected (x+3) because the sign must be negative and must multiply to -15

$\frac{2(x - 5)}{(x - 5)(x + 3)}$

now cancel (x-5)

$\frac{2}{(x + 3)}$

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I need help with my<br> math

Zinaida [17]

Answer:

Slope: 2

a: 5

b: 6

y-coordinate when x = 0: -2

Step-by-step explanation:

To find the slope, you need to divide the change in the y values between two points on a line by their change in x values. The two complete points given are (6, 10) and (2, 2), so doing this for them would be...

(10-2)/(6-2) = 8/4 = 2, so your slope is 2

To find a, you must use this slope by counting from one of the points. For every one you go to the right, you go up two. So, how many times do you need to go up 2 (slope), from 2 (starting point's y coordinate), to get to 8 (target point's y coordinate)? (8-2)/2 = 6/2 = 3, so 3 times. Add that to 2 (starting point's x coordinate) to get 5, so a is 5.

To find b, you can just use (6, 8). You know you're going to the LEFT one, so you must go DOWN 2. Subtract 2 from 8 to get 6.

For the last question, do the same with (2, 2). You're going LEFT 2, so you're going DOWN 4. Subtract 4 from 2 to get -2.

Let me know if you need a more in-depth explanation on any part of this!

8 0

2 years ago

Craig and Alissa are building a sandcastle on the beach. They each have a bucket. Craig's bucket holds 1/2 pound of sand and Ali

Nitella [24]

<h3>Amount of sand craig and Alissa collect together at one time is 1.4 pounds</h3>

<em><u>Solution:</u></em>

Given that,

Craig and Alissa are building a sandcastle on the beach. They each have a bucket

Craig's bucket holds 1/2 pound of sand and Alissa's bucket holds 9/10 pound of sand

Therefore,

$Craig\ bucket = \frac{1}{2}\ pound\\\\Alissa\ bucket = \frac{9}{10}\ pound$

<em><u>How much sand can craig Alissa collect together at one time</u></em>

Add both, we get

$Collect\ together = \frac{1}{2} + \frac{9}{10}\\\\Collect\ together = \frac{1 \times 5}{2 \times 5} + \frac{9}{10}\\\\Collect\ together = \frac{5}{10} + \frac{9}{10}\\\\Collect\ together = \frac{9+5}{10}\\\\Collect\ together = \frac{14}{10} = \frac{7}{5} = 1.4\\\\In\ mixed\ fractions,\\\\Collect\ together = 1\frac{2}{5}$

Thus, amount of sand craig and Alissa collect together at one time is 1.4 pounds

4 0

3 years ago

A commuter crosses one of three bridges, A, B, or C, to go home from work. The commuter crosses bridge A with probability 1/3, c

mihalych1998 [28]

Answer:

0.1333 = 13.33% probability that bridge B was used.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Arrives home by 6 pm

Event B: Bridge B used.

Probability of arriving home by 6 pm:

75% of 1/3(Bridge A)

60% of 1/6(Bridge B)

80% of 1/2(Bridge C)

$P(A) = 0.75*\frac{1}{3} + 0.6*\frac{1}{6} + 0.8*\frac{1}{2} = 0.75$

Probability of arriving home by 6 pm using Bridge B:

60% of 1/6. So

$P(A \cap B) = 0.6*\frac{1}{6} = 0.1$

Find the probability that bridge B was used.

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.1}{0.75} = 0.1333$

0.1333 = 13.33% probability that bridge B was used.

8 0

3 years ago

i need help please! I think I know the answer but for some reason my brain's telling me that it's wrong so if someone could expl

Ivenika [448]

Considering the slopes of the segments, the correct option is:

D. No, because the triangle ABC doesn't have a pair of perpendicular sides.

<h3>When are lines parallel, perpendicular or neither?</h3>

The slope, given by <u>change in y divided by change in x</u>, determines if the lines are parallel, perpendicular, or neither, as follows:

If they are equal, the lines are parallel.

If their multiplication is of -1, they are perpendicular.

Otherwise, they are neither.

Here, we have to find if there are perpendicular segments, that is, if two slopes multiplied have a value of -1, then:

mAB = (-7 - 9)/(11 - 1) = -8/5.

mAC = (3 - 9)/(-9 - 1) = 3/5.

mBC = (3 - (-7))/(-9 - 11) = -1/2.

No sides are perpendicular, hence option D is correct.

More can be learned about slopes at brainly.com/question/20847660

#SPJ1

6 0

1 year ago

Factor the expression.

tiny-mole [99]

B. (k+10f)(k-5f) you can tell in 2 ways. 1. if the second sign is neg then the signs in the factors are going to be one neg and one positive so that knocks out C and D. Then you look at the second term and since the 5 is positive then the 10 has to be positive so you end up with a positive 5kf.

The second way is to FOIL them out. When you check B you get $k^{2} -5kf+10kf- 50f^{2}$ combine your like terms and you have your original expression of $k^{2} +5kf-50 f^{2}$

Hope that helps

3 0

3 years ago